我一直致力于一个程序,要求用户输入一个名单。输入这些名称后,我的程序必须正确对齐所有这些名称。这就是我到目前为止所做的:
names =[]
# User is prompted to enter a list of names
name = input ("Enter strings (end with DONE):\n")
while name != 'DONE':
names.append(name) # This appends/adds the name(s) the user types in, to names
name = input("")
print("\n""Right-aligned list:")
for name in names:
maximum = max(names, key=len) #This line of code searches for the name which is the longest
new_maximum = len(maximum) #Here it determines the length of the longest name
diff = new_maximum - len(name) #This line of code is used to subtract the length of the longest name from the length of another different name
title = diff*' ' #This code determines the open space (as the title) that has to be placed in front of the specific name
print(title,name)
这是没有所有评论的程序:
names =[]
name = input ("Enter strings (end with DONE):\n")
while name != 'DONE':
names.append(name)
name = input("")
print("\n""Right-aligned list:")
for name in names:
maximum = max(names, key=len)
new_maximum = len(maximum)
diff = new_maximum - len(name)
title = diff*' '
print(title,name)
我想要这个程序的输出是:
Enter strings (end with DONE):
Michael
James
Thabang
Kelly
Sam
Christopher
DONE
Right-aligned list:
Michael
James
Thabang
Kelly
Sam
Christopher
相反,这就是我得到的:
Enter strings (end with DONE):
Michael
James
Thabang
Kelly
Sam
Christopher
DONE
Right-aligned list:
Michael
James
Thabang
Kelly
Sam
Christopher
注意:当用户输入DONE时,提示结束。
问题是列表中的每个名称都会打印一个额外的空格。如何打印右对齐但没有额外空格?
答案 0 :(得分:1)
您可以按如下方式使用字符串格式:
a = ['a', 'b', 'cd', 'efg']
max_length = max(len(i) for i in a)
for item in a:
print '{0:>{1}}'.format(item, max_length)
[OUTPUT]
a
b
cd
efg
答案 1 :(得分:1)
我知道这是一个老问题,但这将在一行中完成:
print('\n'.join( [ name.rjust(len(max(names, key=len))) for name in names ] ))
这个列表理解的答案帮助了我:Call int() function on every list element?