Question

我选择了两个日期。

FROM日期：MM / DD / YY

TODATE：MM / DD / YY，

所以我想要排除周末的功能，所以我尝试了这个......

  function onblur(event){
      GetDaysBetweenDates();
  }

      function GetDaysBetweenDates(){     
          if(document.getElementById('datepicker3').value != ""){
              var fromDate = new Date(document.getElementById('datepicker2').value);
              var toDate = new Date(document.getElementById('datepicker3').value);        
              var timeDiff = Math.abs(toDate.getTime() - fromDate.getTime());
              var days = Math.ceil(timeDiff / (1000 * 3600 * 24));  

              if(days){
                    // Subtract two weekend days for every week in between
                    var weeks = Math.floor(days / 7);
                    days = days - (weeks * 2);

                    // Handle special cases
                    var startDay = fromDate.getDay();
                    var endDay = toDate.getDay();

                    // Remove weekend not previously removed.
                    if (startDay - endDay > 1)
                        days = days - 2;

                    // Remove start day if span starts on Sunday but ends before Saturday
                    if (startDay == 0 && endDay != 6)
                        days = days - 1;

                    // Remove end day if span ends on Saturday but starts after Sunday
                    if (endDay == 6 && startDay != 0)
                        days = days - 1;
                }

              $("#txtno_of_leaves").val(diffDays);
          }
      }

但是这个没有用..

Answer 1

试试这个

function workingDaysBetweenDates(startDate, endDate, getWorkingDays) {

    startDate = new Date(startDate);
    endDate = new Date(endDate);

    // Validate input
    if (endDate < startDate)
        return 0;

    // Calculate days between dates
    var millisecondsPerDay = 86400 * 1000; // Day in milliseconds
    startDate.setHours(0,0,0,1);  // Start just after midnight
    endDate.setHours(23,59,59,999);  // End just before midnight
    var diff = endDate - startDate;  // Milliseconds between datetime objects
    var days = Math.ceil(diff / millisecondsPerDay);

    if(getWorkingDays){
        // Subtract two weekend days for every week in between
        var weeks = Math.floor(days / 7);
        days = days - (weeks * 2);

        // Handle special cases
        var startDay = startDate.getDay();
        var endDay = endDate.getDay();

        // Remove weekend not previously removed.
        if (startDay - endDay > 1)
            days = days - 2;

        // Remove start day if span starts on Sunday but ends before Saturday
        if (startDay == 0 && endDay != 6)
            days = days - 1;

        // Remove end day if span ends on Saturday but starts after Sunday
        if (endDay == 6 && startDay != 0)
            days = days - 1;
    }
    return days;
}

workingDaysBetweenDates(start_date, end_date, true);

以下是工作小提琴：http://jsfiddle.net/kailashyadav/YXTX3/

日期格式需要为以下格式之一：04/24/2014或2014-04-24

如何在jquery中排除周末日？

1 个答案: