我使用以下代码构建了一个从用户那里获得输入的简单Python程序。
Name = raw_input('Enter your name: ')
Age = raw_input('Enter you age:')
Qualifications = raw_input('Enter you Qualification(s):')
A = raw_input()
print "Hello" +'.'+ "Your Name is " + Name + ". " + "Your Age is " + Age + ". " + "Your Qualification(s) is/are:" + Qualifications + "."
print "If the above data is correct, type yes. If not, type no. Typing no will restart he program and make you write the form again." + A
if A in ['y', 'Y', 'yes', 'Yes', 'YES']:
print 'Thanks for your submission'
if A in ['No' , 'no' , 'NO' ,'n' , 'N']:
reload()
程序在if命令之前完成。
答案 0 :(得分:2)
如果您提供['y', 'Y', 'yes', 'Yes', 'YES']
或['No' , 'no' , 'NO' ,'n' , 'N']
以外的任何内容,您的计划将完成,而不会执行各自if
- 条款中的任何陈述。
reload()
功能无法达到预期效果。它用于重新加载模块,应该在解释器中使用。它还需要先前导入的module
作为参数,调用它时不会引发TypeError
。
因此,为了实际再次提出问题,您需要一个循环。例如:
while True:
name = raw_input('Enter your name: ')
age = raw_input('Enter your age: ')
qualifications = raw_input('Enter your Qualification(s): ')
print "Hello. Your name is {}. Your age is {}. Your qualifications are: {}".format(name, age, qualifications)
quit = raw_input("Is the above data correct [yY]? ").lower() # notice the lower()
if quit in ("y", "yes"):
break
else:
# If the input was anything but y, yes or any variation of those.
# for example no, foo, bar, asdf..
print "Rewrite the form below"
如果您现在输入的不是y, Y
或yes
的任何变体,程序将再次提出问题。
答案 1 :(得分:0)
在您打印“您的名字是......”之后移动A raw_input
行。像这样:
我还让脚本继续要求重启,直到输入有效。
Name = raw_input('Enter your name: ')
Age = raw_input('Enter you age:')
Qualifications = raw_input('Enter you Qualification(s):')
print "Hello" +'.'+ "Your Name is " + Name + ". " + "Your Age is " + Age + ". " + "Your Qualification(s) is/are:" + Qualifications + "."
print "If the above data is correct, type yes. If not, type no. Typing no will restart he program and make you write the form again."
yes = ['y', 'Y', 'yes', 'Yes', 'YES']
no = ['No' , 'no' , 'NO' ,'n' , 'N']
A = ''
while A not in (yes+no): # keep asking until the answer is a valid yes/no
A = raw_input("Again?: ")
if A in yes:
print 'Thanks for your submission'
if A in no:
reload()