想知道是否有人可以帮助我指出正确的方向，或者告诉我，我通过sql尝试这个很疯狂。如果sql太具挑战性，是否有任何免费或廉价的工具可以帮助我实现自动化？
我正在测试旧的和新的Oracle数据库之间的一些数据。我想做的是能够为模式中的所有表动态生成此查询。
Select Column_1, Column_2 FROM Table_1
MINUS
Select Column_1, Column_2 FROM Table_1@"OLD_SERVER"
一个问题是，为每个表选择的列应该只是不以＆＃39; ETL＆＃39;开头的列。因为这些预计会随着迁移而改变。
为了保持动态，我可以使用all_tab_columns循环遍历每个表吗？
因此，对于一个简化示例，我们假设此查询返回了以下结果，并且您可以预期ALL_TAB_COLUMNS的结果在OLD和NEW数据库之间是相同的：
select TABLE_NAME, COLUMN_NAME from ALL_TAB_COLUMNS where owner = 'OWNER1'
TABLE_NAME, COLUMN_NAME
-----------------------
TABLE1, COLUMN_1
TABLE1, COLUMN_2
TABLE1, ETLCOLUMN_3
TABLE2, COLUMN_A
TABLE2, COLUMN_B
TABLE2, ETLCOLUMN_C
如何在旧数据库和新数据库上编写将在相同表和列（不以ETL开头）之间运行减号的查询，并输出结果以及表名和运行日期，以及然后循环到下一个表并做同样的事情？
答案 0 :(得分：2)
首先 - 看看这个： http://docs.oracle.com/cd/E11882_01/server.112/e41481/spa_upgrade.htm#RATUG210
第二 - 您想编写一个发出查询的查询 - 问题是在user_tab_columns中每列都是一行。
为此，我建议你阅读：http://www.dba-oracle.com/t_converting_rows_columns.htm
您的源表是USER_TAB_COLUMNS，在运行查询时，您可以添加一个说＆＃34;其中column_name不喜欢＆＃39; ETL％＆＃39;等等
之后 - 查询看起来像：
选择＆＃39;选择＆＃39;
|| listagg..... (from the link) || 'from table name' sql
from user_tab_columns
where column_name not like 'ETL%'
and table_name = 'table name'
group by table_name
并且顺便说一句 - 你并不疯狂 - 在更换系统之前，你需要能够签署升级才能成功 - 这是唯一的方法。
顺便说一句 - 如果您更深入地描述系统和升级 - 我相信社区将能够帮助您找到更深入地测试它的方法，并会指出您要测试的东西。好运！
答案 1 :(得分：0)
此测试可以使用SQL和PL / SQL自动执行。这样做你并不疯狂。像这样的比较系统对于测试复杂系统的变化非常有用。它不如自动化单元测试好，但它可以显着增强典型的数据库测试。
以下代码是一个完整的示例。但在现实世界中，有许多问题可能需要几天才能解决。例如，处理CLOB，大表，时间戳和基于序列的值等
示例模式和数据差异
create user schema1 identified by schema1;
create user schema2 identified by schema2;
alter user schema1 quota unlimited on users;
alter user schema2 quota unlimited on users;
--Data in 1, not 2.
create table schema1.table1 as select 1 a, 1 b from dual;
create table schema2.table1(a number, b number);
--Data in 2, not 1.
create table schema1.table2(a number, b number);
create table schema2.table2 as select 1 a, 1 b from dual;
--Same data in both, excluding unused column.
create table schema1.table3 as select 1 a, 1 b, 'asdf' ETL_c from dual;
create table schema2.table3 as select 1 a, 1 b, 'fdsa' ETL_c from dual;
--Table DDL difference.
create table schema1.table4(a number);
create table schema2.table4(b number);
--Privileges can be tricky.
grant select on dba_tab_columns to <your schema>;
打印差异脚本的步骤
create or replace procedure print_differences(
p_old_schema in varchar2,
p_new_schema in varchar2) authid current_user
is
v_table_index number := 0;
v_row_count number;
begin
--Print header information.
dbms_output.put_line('--Comparison between '||p_old_schema||' and '||
p_new_schema||', at '||to_char(sysdate, 'YYYY-MM-DD HH24:MI')||'.'||chr(10));
--Create a SQL statement to return the differences for each table.
for differences in
(
--Return number of differences and SQL statements to view them.
select
'
with old_table as (select '||column_list||' from '||p_old_schema||'.'||table_name||')
, new_table as (select '||column_list||' from '||p_new_schema||'.'||table_name||')
select * from
(
select ''OLD'' old_or_new, old_table.* from old_table minus
select ''OLD'' old_or_new, new_table.* from new_table
)
union all
select * from
(
select ''NEW'' old_or_new, new_table.* from new_table minus
select ''NEW'' old_or_new, old_table.* from old_table
)
' difference_sql, table_name
from
(
select table_name
,listagg(column_name, ',') within group (order by column_id) column_list
from dba_tab_columns
where owner = p_old_schema
and column_name not like 'ETL%'
group by table_name
) column_lists
) loop
begin
--Print table information:
v_table_index := v_table_index+1;
dbms_output.put_line(chr(10)||'--'||lpad(v_table_index, 3, '0')||': '||differences.table_name);
--Count differences.
execute immediate 'select count(*) from ('||differences.difference_sql||')' into v_row_count;
--Print SQL statements to investigate differences.
if v_row_count = 0 then
dbms_output.put_line('--No differences.');
else
dbms_output.put_line('--Differences: '||v_row_count);
dbms_output.put_line(differences.difference_sql||';');
end if;
exception when others then
dbms_output.put_line('/*Error with this statement, possible DDL difference: '
||differences.difference_sql||dbms_utility.format_error_stack||
dbms_utility.format_error_backtrace||'*/');
end;
end loop;
end;
/
运行程序
begin
print_differences('SCHEMA1', 'SCHEMA2');
end;
/
示例输出
该程序不输出实际差异。如果存在差异，则会输出一个显示差异的脚本。使用体面的IDE，这将是一种更好的查看数据的方式，它还有助于进一步分析差异。
--Comparison between SCHEMA1 and SCHEMA2, at 2014-03-28 23:44.
--001: TABLE1
--Differences: 1
with old_table as (select A,B from SCHEMA1.TABLE1)
, new_table as (select A,B from SCHEMA2.TABLE1)
select * from
(
select 'OLD' old_or_new, old_table.* from old_table minus
select 'OLD' old_or_new, new_table.* from new_table
)
union all
select * from
(
select 'NEW' old_or_new, new_table.* from new_table minus
select 'NEW' old_or_new, old_table.* from old_table
)
;
--002: TABLE2
--Differences: 1
with old_table as (select A,B from SCHEMA1.TABLE2)
, new_table as (select A,B from SCHEMA2.TABLE2)
select * from
(
select 'OLD' old_or_new, old_table.* from old_table minus
select 'OLD' old_or_new, new_table.* from new_table
)
union all
select * from
(
select 'NEW' old_or_new, new_table.* from new_table minus
select 'NEW' old_or_new, old_table.* from old_table
)
;
--003: TABLE3
--No differences.
--004: TABLE4
/*Error with this statement, possible DDL difference:
with old_table as (select A from SCHEMA1.TABLE4)
, new_table as (select A from SCHEMA2.TABLE4)
select * from
(
select 'OLD' old_or_new, old_table.* from old_table minus
select 'OLD' old_or_new, new_table.* from new_table
)
union all
select * from
(
select 'NEW' old_or_new, new_table.* from new_table minus
select 'NEW' old_or_new, old_table.* from old_table
)
ORA-06575: Package or function A is in an invalid state
ORA-06512: at "JHELLER.PRINT_DIFFERENCES", line 48
*/