这个查询中有什么错误,不删除

时间:2014-03-27 04:25:08

标签: php mysql sql sqlite csv

我正在使用echo $fss显示数据

  

“11-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V5703211-V57032”

但是我使用的是使用此变量的删除查询,但它无法正常工作

<?php  

 //connect to the database 
 $connect = mysql_connect("localhost","root",""); 
 mysql_select_db("cityshoes",$connect); //select the table 


if ($_FILES[csv][size] > 0) { 

    //get the csv file 
    $file = $_FILES['csv']['tmp_name'];
    $handle = fopen($file,"r"); 



    do { 
        if ($data[0]) { 

 $fss = addslashes($data[1]);
        $result = mysql_query("DELETE from  contacts where articleno = . $fss . ");

        echo $fss;


        } 
    } while ($data = fgetcsv($handle,1000,",","'")); 



} 

?> 

2 个答案:

答案 0 :(得分:3)

您在查询中以错误的方式附加变量。试试:

$result = mysql_query("DELETE from  contacts where articleno = $fss");

$result = mysql_query("DELETE from contacts where articleno ='".$fss ."'");

答案 1 :(得分:0)

转动此行

$result = mysql_query("DELETE from  contacts where articleno = . $fss . ");

到此

$result = mysql_query("DELETE from  contacts where articleno =  $fss ");

您必须删除期间。