Question

我有一个我需要根据一个userID从2个表中获取记录的scenerio。假设我的id是31，那么我想从两个表中获取ID 31的记录。我尝试了很多解决方案，但没有一个适合我。请看看并帮助我。

视频表的表格结构：

CREATE TABLE `web_videos` (
  `vID` int(8) NOT NULL auto_increment,
  `userID` int(8) NOT NULL,
  `v_filename` varchar(255) NOT NULL,
  `v_uploadname` varchar(25) NOT NULL,
  `v_short_desc` varchar(255) NOT NULL,
  `v_singerName` varchar(25) NOT NULL,
  `v_approve` tinyint(4) NOT NULL,
  `v_price` decimal(20,2) NOT NULL default '0.00',
  PRIMARY KEY  (`vID`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=latin1;

音频表的表结构：

CREATE TABLE `web_audio` (
  `aID` int(8) NOT NULL auto_increment,
  `userID` int(8) NOT NULL,
  `a_filename` varchar(30) NOT NULL,
  `a_uploadname` varchar(25) NOT NULL,
  `a_genre` int(8) NOT NULL,
  `a_singerName` varchar(25) NOT NULL,
  `a_approve` tinyint(1) NOT NULL,
  `a_price` decimal(20,2) NOT NULL default '0.00',
  PRIMARY KEY  (`aID`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1;

我得到的记录集是：

3   31  test    mohsin_781.mp3  3   test singer 0   2.50    2   31  asd _639.flv     asdasdd    asd sadasd  0   6.33
4   31  asd mohsin_180.mp3  10  asd 0   7.34    2   31  asd _639.flv     asdasdd    asd sadasd  0   6.33
5   31  mn  _977.mp3    5   lkj 0   8.77    2   31  asd _639.flv     asdasdd    asd sadasd  0   6.33
3   31  test    mohsin_781.mp3  3   test singer 0   2.50    3   31  asdasd  _922.flv    ad asdada da das    adsad   0   6.33
4   31  asd mohsin_180.mp3  10  asd 0   7.34    3   31  asdasd  _922.flv    ad asdada da das    adsad   0   6.33
5   31  mn  _977.mp3    5   lkj 0   8.77    3   31  asdasd  _922.flv    ad asdada da das    adsad   0   6.33
3   31  test    mohsin_781.mp3  3   test singer 0   2.50    4   31  fdgdfg  _745.flv    fdgfdgfdgg dfgdf gd gdf gdf gdf dfg fgd dgdfg   gdfg    0   88.55
4   31  asd mohsin_180.mp3  10  asd 0   7.34    4   31  fdgdfg  _745.flv    fdgfdgfdgg dfgdf gd gdf gdf gdf dfg fgd dgdfg   gdfg    0   88.55
5   31  mn  _977.mp3    5   lkj 0   8.77    4   31  fdgdfg  _745.flv    fdgfdgfdgg dfgdf gd gdf gdf gdf dfg fgd dgdfg   gdfg    0   88.55

MY SQL QUERY：

SELECT
web_audio.aID,
web_audio.userID,
web_audio.a_filename,
web_audio.a_uploadname,
web_audio.a_genre,
web_audio.a_singerName,
web_audio.a_approve,
web_audio.a_price
FROM
web_audio
INNER JOIN web_videos ON web_videos.userID = web_audio.userID
WHERE
web_audio.userID = 31 AND web_videos.userID = 31

你可以看到它复制了记录。所以请让它像我只有用户ID 31的记录，没有重复。

谢谢。

Answer 1

SELECT distinct web_audio.aID,
web_audio.userID,
web_audio.a_filename,
web_audio.a_uploadname,
web_audio.a_genre,
web_audio.a_singerName,
web_audio.a_approve,
web_audio.a_price 
FROM web_audio
INNER JOIN web_videos ON web_videos.userID = web_audio.userID
WHERE
web_audio.userID = 31 AND web_videos.userID = 31

使用distinct来避免重复。

Answer 2

试试这个：

SELECT web_audio.*
FROM web_audio INNER JOIN 
web_videos ON web_videos.userID = web_audio.userID
WHERE
web_audio.userID = 31 AND web_videos.userID = 31
GROUP BY web_audio.aid

请参阅SQL Fiddle中的示例。

由于您只从web_audio选择值，因此请使用：

SELECT * FROM web_audio WHERE userID=31

他们两个都会给出相同的结果。

Answer 3

SELECT
DISTINCT web_audio.aID,
 --the rest of yout query

如何从2个表中获取记录，其中包含来自ID的位置

3 个答案: