Question

我的目标是创建一个dGrid，其中每列都有一个标签和一个名为comments的标签旁边的按钮。

仅当slot_header！=“”时，否则我们将列全部隐藏起来。当我通过它时，我有隐藏的工作。“就在我传递header =“HELLO”时，该列的标签变为：

“HELLO [Widget dijit.form.Button，dijit_form_Button_19]”目标是“HELLO”CLICKABLEBUTTON

我正在使用PHP来实例化网格，然后在renderCell中使用lang.hitch来构建进入domNode的内容，任何帮助都将不胜感激

   $singleStudentDetail = array(
    array('field' => 'line_nbr',     'label' =>'Line',              'properties' => array('width' => $width)),
    array('field' => 'skill_desc',     'label' =>'Skill',               'properties' => array('width' => $width)),
    array('field' => 'display_slot_01', 'label' => 'Notes',
                'properties' => array('width' => 55, 'sortable' => 'false', 'renderCell' =>
                'lang.hitch(this,function(object,value,node,options){

                            node.innerHTML = object["grades_01"];

                        var myButton = new Button({
                                            label: "Click me!",
                                            onClick: function(){
                                                // Do something:
                                                alert("THIS BUTTON WORKED");
                                            }
                                        });
                        if(object["slot_headings_01"] != "")
                        {
                            studentListDetailDGridVar.columns[3].label = object["slot_headings_01"] + myButton
                        }
                        else
                            studentListDetailDGridVar.columns[3].hidden = true;
})'
                )
        ));
$DgridParamsDetail = array(
    "columns"    => $singleStudentDetail,
    "gridVar"    => "studentListDetailDGridVar",
    "gridDiv"    => "studentListDetailDiv",
    "gridProperties"    =>  array("rowsPerPage" => 15),
    "render"        =>  true

);

Answer 1

使用renderCell或renderHeaderCell时，您需要返回按钮的domNode而不是按钮小部件。

下面是一个返回按钮的renderCell函数的javascript示例。

renderCell: function(object, data, td, options) {
    return new Button({
        label: "Click me!",
        onClick: function() {
            console.log("THIS BUTTON WORKED!");
        }
    }).domNode;
}

Dojo DGrid-如何在列的标签中添加按钮？

1 个答案: