Question

我在SQL Server中有一个包含这些记录的表：

ID         Date     Time
--     ---------    ----
1      09/05/02     6:00
2      09/05/02     8:00
3      09/05/03     6:00
4      09/05/04     8:00
5      09/05/04     6:00

我想选择那些在一天中有重复两次或两次的记录的身份证明。

我如何在SQL Server中执行此操作？

Answer 1

类似的东西：

select table_1.id, table_1.date from
table as table_1 inner join table as table_2 on 
table_1.date = table_2.date 
and 
table_1.id <> table_2.id

应该可以正常工作。

Answer 2

这将返回预期结果

     declare @aa table (id int,datee date)
     insert into @aa 
    select 1, '09/05/02' union all
     select 2, '09/05/02' union all
    select 3, '09/05/03' union all
    select 4, '09/05/04' union all
    select 5, '09/05/04'    

     select * from @aa where datee in (
                select datee from @aa group by datee having COUNT(datee)>1)

Answer 3

此查询只选择ID = 1的记录和重复两次或多次2的日期：

SELECT  *
FROM     MyTable
WHERE  (Date IN
          (SELECT  Date
           FROM  MyTable
           WHERE  (ID = 1)
           GROUP BY Date
          HAVING  (COUNT(Date) % 2 = 0)
          )
       )
 AND (ID = 1)

Answer 4

修改

CREATE TABLE MyTable(ID INTEGER, Date DATETIME)

INSERT INTO MyTable VALUES (1, '09/05/02 6:00')
INSERT INTO MyTable VALUES (1, '09/05/02 8:00')
INSERT INTO MyTable VALUES (2, '09/05/03 6:00')
INSERT INTO MyTable VALUES (3, '09/05/04 8:00')
INSERT INTO MyTable VALUES (4, '09/05/04 6:00')

SELECT  t1.*
FROM    MyTable t1
        INNER JOIN (
          SELECT  t1.ID, Date1 = t1.Date, Date2 = t2.Date
          FROM    MyTable t1
                  INNER JOIN MyTable t2 ON CAST(t2.Date AS INTEGER) = CAST(t1.Date AS INTEGER)
                                           AND DATEPART(HOUR, t2.Date) = DATEPART(HOUR, t1.Date) - 2
                                           AND t2.ID = t1.ID
        ) t2 ON t2.ID = t1.ID AND t1.Date IN (t2.Date1, t2.Date2)

Answer 5

我的布局对于我来说不是很清楚日期和时间是在单独的列中，还是只有一列。那就是，你有

ID    theDate    theTime
--    --------   -------
1     09/05/02   6:00
1     09/05/02   8:00
2     09/05/03   6:00
3     09/05/04   8:00
4     09/05/04   6:00

或

ID    theDateTime
--    -------------
1     09/05/02 6:00
1     09/05/02 8:00
2     09/05/03 6:00
3     09/05/04 8:00
4     09/05/04 6:00

如果第一个是真的，那么Ramesh几乎（但不完全是）正确的答案：

select *
from theTable
where theDate in (
    select theDate 
    from theTable
    group by theDate
    having count(theDate) % 2 = 0
)

如果第二个是真的，那么你的工作要复杂得多 - 我会考虑一下。

选择重复两次的记录！

5 个答案:

修改