Question

我是slowly learning如何使用matplotlib制作数字动画。现在，我有一个条形图，我想在每个新框架中添加一个新的框架（并调整其他框架的宽度和高度）。

这是我到目前为止所做的。

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import animation

fig = plt.figure()

ax = plt.subplot(1,1,1)

N = 10

plt.xlim(0,10)
plt.ylim(0,10)

x = np.arange(N)
y = np.zeros(N)

bars = plt.bar(x,y,1)

for bar in bars:
    ax.add_patch(bar)

def init():
    for bar in bars:
        bar.set_height(0.)
    return [bar for bar in bars]

# animation function.  This is called sequentially
def animate(i):
    for j, bar in enumerate(bars):
        bar.set_height(j+i)
        bar.set_width(bar.get_width()/float(i+1))
    return [bar for bar in bars]

anim = animation.FuncAnimation(fig, animate, init_func=init,
                               frames = 10, interval=200, blit=True)
plt.show()

因此，在上面的代码中，animate应为[1; 10]中的每个i添加一个新栏，从10个柱开始，然后是11个，......，最后是20个。

问题：我该怎么办？

由于

Answer 1

您可以这样做：

import numpy as np
import matplotlib.pyplot as plt
from matplotlib import animation

fig = plt.figure()

ax = plt.subplot(1,1,1)

N = 10
M = 10

plt.xlim(0,N+M)
plt.ylim(0,N+M)

x = np.arange(N+M)
y = np.arange(N+M)

bars = [b for b in plt.bar(x[:N],y[:N],1)]

def init():
    return bars

# animation function.  This is called sequentially
def animate(i):
    if i<M:
        bars.append(plt.bar(x[N+i],y[N+i],1)[0]) 
    return bars

anim = animation.FuncAnimation(fig, animate, init_func=init,
                               frames = 10, interval=200, blit=True)
plt.show()

在matplotlib中的动画的每次迭代中添加新的bin

1 个答案: