Question

我正在尝试创建一个文本冒险游戏但是当我尝试运行它时，我在“battle_input = battle_input.lower（）”和“if battle_input ==”攻击“：”时收到错误你能告诉我什么错了吗？

def battle(monster):
print "You have encountered a %s" % (str(monster))
while hero_health > 0 or monster.health > 0:
    battle_input = input("Would you like to attack, use magic, use item, or retreat?"
    battle_input = battle_input.lower()
    if battle_input == "attack":
        print "You attack with your %s!" % (weapon)
        damage = random.randint(hero_attack, player_attack + 5)
        print "The %s takes %s damage!" % (monster, str(damage))
        monster.health -= damage
        if monster.health <= 0:
            print "You slayed the %s!" % (monster)
            break
    #add the others
    print "The %s attacks!" % (monster)
    monster_damage = random.randint(monster.attack, monster.attack + 5)
    player_health -= damage
else:
        if monster_health <= 0:
            print "Congratulations!"
        else:
            print "Game over."
            game_over = 1

Answer 1

您错过了前一行input行的右括号：

battle_input = input("Would you like to attack, use magic, use item, or retreat?"
#                                                                ----------------^

添加右括号，Python可以理解这一行和下一行。

经验法则：每当遇到看似不合理的奇怪SyntaxError时，检查前一行并确保所有左括号，括号和括号都有匹配的结束字符。

在分配变量和冒号时出错

1 个答案: