Question

如何创建一个bash文件，为从文件夹A移动到文件夹B的每个文件创建符号链接（linux）。 但是，这将从文件夹A中选择150个最大的当前文件。

Answer 1

可以将它写在一个内容中，但在像

这样的简单bash脚本中更容易

#!/bin/bash
FolderA="/some/folder/to/copy/from/"
FolderB="/some/folder/to/copy/to/"
while read -r size file; do
  mv -iv "$file" "$FolderB"
  ln -s "${FolderB}${file##*/}" "$file"
done < <(find "$FolderA" -maxdepth 1 -type f -printf '%s %p\n'| sort -rn | head -n150)

注意${file##*/}会移除上一个/之前的所有内容，每个

   ${parameter##word}
          Remove matching prefix pattern.  The word is expanded to produce a pattern just as in  pathname  expansion.   If  the
          pattern  matches  the  beginning of the value of parameter, then the result of the expansion is the expanded value of
          parameter with the shortest matching pattern (the ``#'' case) or the  longest  matching  pattern  (the  ``##''  case)
          deleted.   If parameter is @ or *, the pattern removal operation is applied to each positional parameter in turn, and
          the expansion is the resultant list.  If parameter is an array variable subscripted with @ or *, the pattern  removal
          operation is applied to each member of the array in turn, and the expansion is the resultant list.

此外，仅执行for file in $(command)似乎是一个好主意，但过程替换和while/read works better in general to avoid word-splitting issues like splitting up files with spaces, etc...

Answer 2

与任何任务一样，将其分解成更小的部分，事情就会落到实处。

从FolderA
中选择最大的150个文件

可以使用du，sort和awk来完成此操作，您将其输出放入数组中：

du -h /path/to/FolderA/* | sort -h | head -n150 | awk '{print $2}'

将文件从FolderA移至FolderB

从最后一个命令中取出列表，然后迭代它：

for file in ${myarray[@]}; do mv "$file" /path/to/FolderB/; done

为新位置创建符号链接

再次，只需遍历列表：

for file in ${myarray[@]; do ln -s "$file" "/path/to/FolderB/${file/*FolderA\/}"; done

如何创建一个bash文件，为从文件夹A移动到文件夹B的每个文件创建一个符号链接（linux）

2 个答案: