Question

好的我有以下代码但是我的sql查询不会显示结果所以我得出结论sql语句一定是错的？

请有人让我知道我做错了什么？

由于

$result=mysqli_query("SELECT * FROM Persons WHERE Day = '".$_POST['Day']."' AND Time = '".$_POST['Time']."'");
echo "Query Runs";

echo "<table border='1'>
<tr>
<th>Name</th>
<th>Day</th>
<th>Time</th>
<th>Reg</th>
</tr>";
echo "Delete a Booking today ";
while($row = mysqli_fetch_array($query))
  {
  echo "<tr>";
  echo "<td>" . $row['Name'] . "</td>";
  echo "<td>" . $row['Day'] . "</td>";
  echo "<td>" . $row['Time'] . "</td>";
  echo "<td>" . $row['Reg'] . "</td>";
  echo "</tr>";
  }
echo "</table>";

sql语句无效，因为以下命令将运行。 $ result = mysqli_query（“SELECT * FROM Persons WHERE Day ='”。$ _ POST ['Day']。“'AND Time ='”。$ _ POST ['Time']。“'”）;

以下都不会返回结果：

$result=mysqli_query("SELECT * FROM Persons WHERE Day = '".$_POST['Day']."' AND Time = '".$_POST['Time']."'";


$result=mysqli_query("SELECT * FROM Persons WHERE Day = '$_POST[Day]' AND Time = '$_POST[Time]' ")

Answer 1

day和time在mysql中保留。

使用返回标记`，以便它们不会将它们作为保留名称读取，而是作为您的表名称。

$query=mysqli_query("SELECT * FROM Persons WHERE `DAY` = '".$_POST['Day']."' AND `Time` = '".$_POST['Time']."'");

此代码也容易受到sql攻击。请正确使用mysqli here。

Answer 2

您忘记执行SQL查询。

$query=mysqli_query("SELECT * FROM Persons WHERE DAY = '".$_POST['Day']."' AND Time = '".$_POST['Time']."'");

sql php where语句无法正常工作

2 个答案: