Question

我已经在 StackOverflow 上研究了这个问题，但所有答案都指定了如何使用已知的加密算法（主要是WEP）连接到网络。在我的应用程序中，我检索可用的wifi网络列表，并在ListView中显示它们（使用WifiManager）。当用户单击列表中的一个项目时，我想连接到网络。

我当前的实现尝试从WifiConfiguration的功能字符串中获取ScanResult数据。例如，这些都是检索到的实际功能字符串：

[WPA2-PSK-CCMP][ESS]
[WPA2-PSK-CCMP+TKIP][ESS]
[WPA-PSK-CCMP+TKIP][WPA2-PSK-CCMP+TKIP][ESS]

根据一些研究，我假设这些是支架分离的功能，每个功能的第一项是-分隔的字符串，显示：

[Authentication Algorithm - Key Management Algorithm - Pairwise Cipher]

我解析这些数据，然后创建一个WifiConfiguration对象，然后尝试连接到它，但它总是失败（addNetwork返回-1）。我究竟做错了什么？这是我的代码：

@Override
public void onItemClick(AdapterView<?> adapter, View parent, int position, long id) {
    ScanResult result = (ScanResult) adapter.getItem(position);
    WifiConfiguration config = new WifiConfiguration();

    String currentNetwork = mWifiManager.getConnectionInfo().getSSID();
    if (currentNetwork != null && currentNetwork.equals(result.SSID))
    {
        Toast.makeText(this, "Already connected", Toast.LENGTH_SHORT).show();
        return;
    }

    config.BSSID = result.BSSID;
    config.SSID = result.SSID;
    String firstCapabilities = result.capabilities.substring(1, result.capabilities.indexOf("]")-1);
    String[] capabilities = firstCapabilities.split("-");
    String auth = capabilities[0];
    String keyMgmt = capabilities[1];
    String pairwiseCipher = capabilities[2];

    int a = 0;
    if (auth.contains("EAP"))
        a |= WifiConfiguration.AuthAlgorithm.LEAP;
    else if (auth.contains("WPA"))
        a |= WifiConfiguration.AuthAlgorithm.OPEN;
    else if (auth.contains("WEP"))
        a |= WifiConfiguration.AuthAlgorithm.SHARED;
    config.allowedAuthAlgorithms.set(a);

    int k = WifiConfiguration.KeyMgmt.NONE;
    if (keyMgmt.contains("IEEE802.1X"))
        k |= WifiConfiguration.KeyMgmt.IEEE8021X;
    else if (auth.contains("WPA") && keyMgmt.contains("EAP"))
        k |= WifiConfiguration.KeyMgmt.WPA_EAP;
    else if (auth.contains("WPA") && keyMgmt.contains("PSK"))
        k |= WifiConfiguration.KeyMgmt.WPA_PSK;
    config.allowedKeyManagement.set(k);

    int c = WifiConfiguration.PairwiseCipher.NONE;
    if (pairwiseCipher.contains("CCMP"))
        c |= WifiConfiguration.PairwiseCipher.CCMP;
    if (pairwiseCipher.contains("TKIP"))
        c |= WifiConfiguration.PairwiseCipher.TKIP;
    config.allowedPairwiseCiphers.set(c);

    int networkId = mWifiManager.addNetwork(config);
    if (networkId == -1)
    {
        //always hits this line!
        Toast.makeText(this, "Failed to create network configuration", Toast.LENGTH_SHORT).show();
    }
    else
    {
        //Never reaches here!
        mWifiManager.disconnect();
        mWifiManager.enableNetwork(networkId, true);
        mWifiManager.reconnect();
    }

}

Answer 1

对于WPA *，如果未将preSharedKey设置为8个或更多字符，则将失败并返回-1。我根本没有看到你设置它。

如何在Android中使用未知加密算法连接到WiFi网络？

1 个答案: