Question

每个人都过得愉快好吧，我有一个登录问题，每次我尝试登录我收到此消息

警告：mysql_query（）：提供的参数不是有效的MySQL-Link 资源在/home/a6720525/public_html/functions/sandbox.php上 25
警告：mysql_num_rows（）：提供的参数不是有效的MySQL /home/a6720525/public_html/functions/sandbox.php中的结果资源第27行

登录表单

 <form class="admin_login" id="form1" name="form1" method="post" action="index.php">

    <input class="username" name="username" type="text" id="username" size"40" placeholder="Adress email"/>

    <input class="userpass" name="password" type="password" id="password" size"40" placeholder="Mot de pass"/>

    <input class="addbutton" type="submit" name="button" value="connexion"/>
    <input class="addbutton" type="submit" name="insc" value="Inscription"/>
    <input class="addbutton" type="submit" name="mpo" value="Mot de pass oublier?"/>
    </form>

我使用的功能

function members ($dbc, $qu) {

if(isset($_POST["username"])&& isset($_POST["password"])){
    $manager = preg_replace('#[^A-Za-z0-9\@\-\_\|\,\.\\p{L}\\\\]#i', '', $_POST["username"]);//filter everything but numbers and letters
    $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]);// filter everything but numbers and letters
    // Connect to the Mysql database
    $qu = "SELECT id FROM users WHERE username='$manager' AND password='$password' LIMIT 1";
    $re = mysql_query($dbc, $qu);
    //........make sure person exists in data base
    $existCount = mysql_num_rows($re);// count the row nums
    if($existCount == 1){//evaluate the count
    while($row = mysql_fetch_array($re )){
        $id = $row["id"];
    }
    $_SESSION["id"] = $id;
    $_SESSION["manager"] = $manager;
    $_SESSION["password"] = $password;
    header("location:index.php");
    exit();
    }else{
        echo 'That information is incorrect,try again <a href="index.php">Click Here</a>';
        exit();
    }
}
}

Answer 1

session_start();
if(isset($_POST["username"])&& isset($_POST["password"])){
    $manager = preg_replace('#[^A-Za-z0-9\@\-\_\|\,\.\\p{L}\\\\]#i', '', $_POST["username"]);//filter everything but numbers and letters
    $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]);// filter everything but numbers and letters
    // Connect to the Mysql database
        $q = "SELECT * FROM users WHERE username='$manager' AND password='$password' LIMIT 1";
        $r = mysqli_query($dbc, $q);
        $userCount = mysqli_num_rows($r);
        if($userCount == 1 ) {
            while ($user = mysqli_fetch_assoc($r)) {

            $id = $user['id'];
            $pass = $user['password'];  
            $us = $user['username'];

            }
                $_SESSION["id"] = $id;
                $_SESSION["manager"] = $us;
                $_SESSION["password"] = $pass;
                header("location:index.php?page=business");
                exit(); 

        }else { echo 'That information is incorrect,try again <a href="index.php">Click Here</a>';
                }


}

PHP登录问题 - mysql_num_rows无效

1 个答案: