field.function - KeyError：40

Question

当我更新它抛出KeyError：40

的值时，创建了一个列'line_no'

我的代码：

def _get_line_no(self, cr, uid, ids, line_no, arg, context=None):
    res = {}
    for record in self.browse(cr, uid, ids, context=context):                     
        nextno =0
        no = record.next_line_no        
        next_no = nextno + no
        total =+ next_no
        res={
                  'next_line_no':next_no,
                  'line_no': total
        } 
    return res

_columns = {
 'line_no':fields.function(_get_line_no,string='Line No',type='integer'),
 'next_line_no':fields.integer(' Next Line No'),
  }
_defaults = {
    'next_line_no':1  
  }

引发错误：KeyError：40

我如何解决？

Answer 1

next_line_no是一个数据库字段，因此它不会影响动态方式。

你需要修改这种方式，

def _get_line_no(self, cr, uid, ids, line_no, arg, context=None):
    res = {}
    for record in self.browse(cr, uid, ids, context=context):                     
        nextno =0
        no = record.next_line_no        
        next_no = nextno + no
        total += next_no
        res[record.id]={
                  'next_line_no':next_no,
                  'line_no': total
        } 
    return res

_columns = {
 'line_no':fields.function(_get_line_no,string='Line No',type='integer', multi="lineno"),
 'next_line_no': function(_get_line_no,string='Next Line No',type='integer', multi="lineno", store=True),
  }
_defaults = {
    'next_line_no':1  
  }

我希望这会让你感到高兴。

Answer 2

按列更改列，

_columns = {
    'line_no':fields.function(_get_line_no,string='Line No',type='integer', multi="line"),
    'next_line_no':fields.function(_get_line_no, type='integer', string='next line number' ,multi="line"),
}

和你的方法一样，

def _get_line_no(self, cr, uid, ids, field_names, args, context=None):
    res = {}
    for record in self.browse(cr, uid, ids, context=context):                     
        nextno =0
        no = record.next_line_no        
        next_no = nextno + no
        total += next_no
        res[record.id]={
                  'next_line_no':next_no,
                  'line_no': total
        } 
    return res

这样可行。