Question

在不使用web.xml的情况下，我有哪些选项可以捕获和处理404。这就是我定义Servlet的方式：

@Order(1)
public class MyWebApplicationInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    // 10MB
    private static final int MAX_UPLOAD_SIZE_IN_MB = 10 * 1024 * 1024;

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class[] { RootConfiguration.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class[] { WebConfiguration.class };
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }

    @Override
    protected Filter[] getServletFilters() {
        return new Filter[] { new SiteMeshFilter() };
    }

    @Override
    protected void customizeRegistration(ServletRegistration.Dynamic registration) {
        MultipartConfigElement multipartConfigElement = new MultipartConfigElement("/tmp", MAX_UPLOAD_SIZE_IN_MB, MAX_UPLOAD_SIZE_IN_MB * 2,
                MAX_UPLOAD_SIZE_IN_MB / 2);
        registration.setMultipartConfig(multipartConfigElement);
    }

}

我的应用程序都是用java代码配置的，@ControllerAdvice适用于所有其他异常，例如：

BindException.class, MethodArgumentNotValidException.class, MissingServletRequestParameterException.class,
MissingServletRequestPartException.class, HttpMessageNotReadableException.class, TypeMismatchException.class

然而

@ControllerAdvice
public class SomeClass {
...
    @ExceptionHandler(value = { ResourceNotFoundException.class, NoSuchRequestHandlingMethodException.class })
    public ModelAndView handle404() {
        ModelAndView modelAndView = new ModelAndView();
        modelAndView.setViewName("/errors/404");
        modelAndView.addObject("exception", "404 NOT FOUND!");
        return modelAndView;
    }
...
}

没有抓住404 我也试过HttpStatus ......没有运气

当我打电话给/ someUrlThatDoesNotExist：

[DEBUG] 2014-01-24 10:03:16,639 org.springframework.security.web.FilterChainProxy doFilter - /someUrlThatDoesNotExist reached end of additional filter chain; proceeding with original chain
[DEBUG] 2014-01-24 10:03:16,640 org.springframework.web.servlet.DispatcherServlet doService - DispatcherServlet with name 'dispatcher' processing GET request for [/someUrlThatDoesNotExist]
[DEBUG] 2014-01-24 10:03:16,641 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping getHandlerInternal - Looking up handler method for path /someUrlThatDoesNotExist
[DEBUG] 2014-01-24 10:03:16,662 org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping getHandlerInternal - Did not find handler method for [/someUrlThatDoesNotExist]
[WARN] 2014-01-24 10:03:16,663 org.springframework.web.servlet.PageNotFound noHandlerFound - No mapping found for HTTP request with URI [/someUrlThatDoesNotExist] in DispatcherServlet with name 'dispatcher'
[DEBUG] 2014-01-24 10:03:16,665 org.springframework.web.servlet.DispatcherServlet processRequest - Successfully completed request

但是当我尝试使用AOP检查以下切点时：

org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver.handleHttpRequestMethodNotSupported(..)
org.springframework.web.servlet.mvc.support.DefaultHandlerExceptionResolver.handleNoSuchRequestHandlingMethod(..)

他们永远不会被抓住..

Answer 1

我认为如果没有找到处理程序，您需要配置DispatcherServlet以抛出异常

dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);

然后让@ControllerAdvice为@ExceptionHandler类型的例外声明NoHandlerFoundException。

Spring 3.2 servlet 3.0 Java Config（无web.xml）如何创建自定义404处理程序

1 个答案: