如何从bat中的完整路径中提取文件名？

Question

变量%result%包含路径"D:\My Folder1\My Folder 2\My Folder 3\The Important File.txt"。我想将The Important File存储在另一个变量中。也就是说，我想从完整路径中提取文件名（无扩展名）。

Answer 1

您可以在此处找到解决方案：Get the file name from a full or relative path knowing that this one is not a parameter of the batch

此处：Get filename from string-path?

此处：In Batch: Read only the filename from a variable with path and filename

请在创建重复项之前搜索现有问题。

Answer 2

这应该可以满足您的需求。

@echo off
for %%a in ("%result%") do set "newvariable=%%~na"