rsync如何用空格排除所有数组？

Question

目录：

$ cd /source/xxx/ && find deleteme/
deleteme/
deleteme/file
deleteme/ex me
deleteme/ex me/nono
deleteme/ex me/nono/a
deleteme/ex me/touch

脚本：

#!/bin/bash

SOURCE=/source/xxx/deleteme/
TARGET=/media/xxx/
EXCLUDE=("ex me/*")
INCLUDE=("ex me/touch")


for i in "${!EXCLUDE[@]}"
do
  EXCLUDE[i]="--exclude=${EXCLUDE[i]}"
done

for i in "${!INCLUDE[@]}"
do
  INCLUDE[i]="--include=${INCLUDE[i]}"
done

rsync -avR --delete ${INCLUDE[@]} ${EXCLUDE[@]} "${SOURCE}" "${TARGET}"

结果：

$ cd /media/xxx/ && find deleteme/
deleteme/
deleteme/ex me
deleteme/ex me/nono
deleteme/ex me/nono/a
deleteme/ex me/touch
deleteme/file

预期结果：

$ cd /media/xxx/ && find deleteme/
deleteme/
deleteme/ex me
deleteme/ex me/touch
deleteme/file

问题

如何获得预期结果？

没有空间＆＃34; exme＆＃34;它有效。

Answer 1

您在实际的rsync调用中缺少引号：

rsync -avR --delete "${INCLUDE[@]}" "${EXCLUDE[@]}" "${SOURCE}" "${TARGET}"
#...................^.............^.^.............^

这对于让bash将数组扩展为元素至关重要。