Question

我的程序应该收到大量的资金，并将其转换为更改，但是当它收到0时，它应该停止要求输入并停止程序。

我的所有数学都是正确的，我只是在重复询问数字时遇到问题。这是我目前的情况：

public class Coins {

    public static int quarters;
public static int dimes;
public static int nickels;
public static int pennies;

    public static int Quarters(int TotalCoins) {
        quarters = (int) (TotalCoins / 25);
        TotalCoins %= 25;
        return quarters;
    }
    public static int Dimes(int TotalCoins){
        TotalCoins -= (quarters * 25);
        dimes = (int) (TotalCoins / 10);
        TotalCoins %= 10;
        return dimes;
}
    public static int Nickels(int TotalCoins){
        TotalCoins -= (dimes * 10) + (quarters * 25);
        nickels = (int) (TotalCoins / 5);
        TotalCoins %= 5;
        return nickels;
    }
    public static int Pennies(int TotalCoins){
        TotalCoins -= (nickels * 5 ) + (dimes * 10 ) + (quarters * 25);
        pennies = (int) (TotalCoins / 1);
        TotalCoins %= 1;
        return pennies;
    }
}

这是我的测试人员课程（我非常确定我的主要问题是）：

public class CoinsTester {
    public static void main(String[] args) {           
        Scanner kybd = new Scanner(System.in);

        if (kybd.nextInt() != 0){
            int changeMoney = kybd.nextInt();
            System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " + Coins.Pennies(changeMoney));              
        }
    }
}

任何帮助都会很棒。

编辑：有人告诉我，在一个班级中完成整个任务可能更容易，如果是这样的话，任何以这种方式做的建议都会很好。三江源！
编辑：我忘了提到我应该能够输入所有数字，然后显示所有数字的输出。

Answer 1

你想要这样的东西：

Scanner kybd = new Scanner(System.in);

while (true) { 
    int changeMoney = kybd.nextInt();
    if (changeMoney == 0)
        break;

    // do stuff with changeMoney
}

它也可以表示为for循环：

Scanner kybd = new Scanner(System.in);
for (int changeMoney = kybd.nextInt(); changeMoney != 0; changeMoney = kybd.nextInt()) {
    // do stuff with changeMoney 
}

虽然线条较少，但它使for循环线很长，但可以通过使用较短的变量名来缓解：

Scanner in = new Scanner(System.in);
for (int i = in.nextInt(); i != 0; i = in.nextInt()) {
    // do stuff with i
}

Answer 2

您要求用户输入两次号码

一旦有条件，

if

秒。

如果您希望让用户再次写入另一个号码，那么您的if似乎应该被循环替换。在这种情况下，您可以使用类似

的内容

Scanner kybd = new Scanner(System.in);
for (int changeMoney = -1; (changeMoney = kybd.nextInt()) != 0;){
    System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " + Coins.Pennies(changeMoney));
}

这种方法的优点是它很短，changeMoney只是局部变量，只能在循环中使用。

Answer 3

首先，您的方法应该具有小写名称。其次，你需要一个循环 - 也许就像这样

public static void main(String[] args) {
  Scanner kybd = new Scanner(System.in);

  while (kybd.hasNextInt()){ // will stop if the next input is not an int.
    int changeMoney = kybd.nextInt();
    if (changeMoney == 0) {
      break;
    }
    // Assuming you just rename them to "get" methods.
    System.out.println("Quarters = "
        + Coins.getQuarters(changeMoney) + "\nDimes = "
        + Coins.getDimes(changeMoney) + "\nNickels = "
        + Coins.getNickels(changeMoney)
        + "\nPennies = "
        + Coins.getPennies(changeMoney));
  }
}

Answer 4

将其更改为此类内容。

 int changeMoney=0;
 while ( (changeMoney =kybd.nextInt()) != 0){           
     System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " + Coins.Pennies(changeMoney));    
 }

@Bohemian回答：很棒的代码。我的错，忘记提及（抱歉）我应该能够一次输入所有输入数字，我该怎么做你会说这个吗？

将输入存储在类似List的集合中。

代码示例：

List<Integer> list = new ArrayList<>();          
while ( (int i =kybd.nextInt()) != 0){           
     list.add(i);
}
// Then loop again
for(Integer changeMoney : list){
     System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " +      Coins.Pennies(changeMoney)); 
}

Answer 5

看起来你只读了一次，你应该在一个while循环中包装scanner.nextInt（）调用，如果值为0就会中断

while (kybd.hasNextInt()){
   int changeMoney = kybd.nextInt();
   if(changeMoney == 0)break;

   System.out.println("Quarters = " + Coins.Quarters(changeMoney) + "\nDimes = " + Coins.Dimes(changeMoney) + "\nNickels = " + Coins.Nickels(changeMoney) + "\nPennies = " + Coins.Pennies(changeMoney));

}

如何请求多个输入并在用户输入0时停止？

5 个答案: