我使用以下代码将我的类序列化为XML字符串:
AXMLItem rc = new AXMLItem();
rc.Attributes.Add(new Reports.ReportConfiguration.Questionnaire.FormObjectXMLItem.Attribute { Value = "ddddd" });
MemoryStream fw = new MemoryStream();
var serializer = new XmlSerializer(typeof(AXMLItem ));
using (StringWriter textWriter = new StringWriter())
{
using (XmlWriter xmlWriter = XmlWriter.Create(textWriter))
{
serializer.Serialize(xmlWriter, rc);
}
string myString = textWriter.ToString(); //This is the output as a string
}
那个班级定义
[XmlType(TypeName = "A")]
public class AXMLItem
{
[XmlType(TypeName = "B")]
public List<Attr> Attrs { get; set; }
[XmlType(TypeName = "C")]
public class Attr
{
[XmlText]
public string Value { get; set; }
}
public AXMLItem()
{
Attrs = new List<Attr>();
}
}
给了我以下字符串
<?xml version="1.0" encoding="utf-16"?>
<A xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<B>
<C>ddddd</C>
</B>
</A>
但我需要
<?xml version="1.0" encoding="utf-16"?>
<A xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<C>ddddd</C>
</A>
明白可能有很多<C>...</C>
个项目。如何解决?
答案 0 :(得分:6)
只需在集合属性中添加XmlElement
属性:
[XmlElement("C")]
public List<Attr> Attrs { get; set; }