Question

我需要为IOS编写一些gui，但我已经习惯了android所拥有的自动视图ID，在识别视图而不在界面构建器中放置显式标记时我感到很茫然

是否有某种方法可以从界面构建器或其他方式自动识别iOS视图？

也许是一个可以做到这一点的图书馆？

Answer 1

这就是为什么你有IBOutlets。为您的视图创建一个IBOutlet，如IBOutlet UIView *view1;等等，然后将IBOutlet链接到Interface Builder中的视图。现在，您可以通过编程方式使用view1变量，该变量将修改与界面构建器中的IBOutlet关联的视图\

<强>更新

以协方式方式创建所有视图：

for(int i = 0; i < 20; i++){
    //set your x and y coordinates with some awesome maths, maybe you want to create a grid, so update the x coordinate accordingly
    UIView *view = [UIView alloc] initWithFrame:CGRectMake(whateverframe)];
    UITapGestureRecognizer *singleTapGesture = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(viewTapped:)];
    [imageView addGestureRecognizer:singleTapGesture];

    [singleTapGesture release]; //remove line if you have an ARC project

    view.tag = i; //this is just for you since you like to handle your views with id tags
}

然后你的一个方法将处理所有代码的点击

- (void) viewTapped:(UIGestureRecognizer*)recognizer
{
     UIView *viewTapped = recognizer.view; // This is the view associated with gesture recognizer.
    int id = viewTapped.tag; //heres the tag id do whatever you like

    //do something with either that view variable which will return the view that was tapped
    //maybe you wanted to change the color of it or something or change the contents of it

    //or you can do something with the id tag of that view.

    //or maybe you just want to handle it with if else statements like so
    //if(viewTapped.tag == 1) //do this
    //elseif(viewTapped.tag == 2) // etc etc
}

Answer 2

使用属性setTag为每个视图设置标记，并使用– viewWithTag:检索相应的视图。 [abaseView subViews]返回一组子视图。使用Class和Tag过滤子视图。

自动视图ID就像在android中一样

2 个答案: