这是我从数据库中提取数据到csv文件的代码。它工作正常,但现在我把它放在数据有地址的程序中,因此有逗号(,),我在打印时遇到问题。
这就是它的样子:
Name Address1 Address2 City Email
Name1 123 Mcarthur San Juan City 12 Jones Manila
应该是这样的:
Name Address1 Address2 City Email
Name1 123 Mcarthur, San Juan City 12 Jones, Manila Manila sample@yahoo.com
城市和电子邮件被推送到另一列。我搜索了互联网,但我看到的只是用逗号(,)来表示的数据。
另外,php中的警告和错误消息也在csv文件中导出。我没有那么多问题,因为一旦我解决这个问题,我认为不会有任何警告。
然后这是我的代码:
if(isset($_POST['csvextract'])){
$name = "sample";
$file = $name.".csv";
$con = mysql_connect("localhost", "root");
if(!$con){
echo "Error connection";
}
$select_db = mysql_select_db('outbound', $con);
if(!$select_db){
echo "Error to select database";
}
mysql_set_charset("utf8", $con);
header("Content-type: text/csv; charset=UTF-8");
header('Content-disposition: attachment; filename='.basename($file));
$myquery = mysql_query("SELECT * FROM temp");
//While loop to fetch the records
$contents = "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
while($row = mysql_fetch_array($myquery))
{
$contents.=$row['0'].",";
$contents.=$row['1'].",";
$contents.=$row['2'].",";
$contents.=$row['3'].",";
$contents.=$row['4'].",";
$contents.=$row['5'].",";
$contents.=$row['6'].",";
$contents.=$row['7'].",";
$contents.=$row['8'].",";
$contents.=$row['9'].",";
$contents.=$row['10'].",";
$contents.=$row['11'].",";
$contents.=$row['12'].",";
$contents.=$row['13'].",";
$contents.=$row['14'].",";
$contents.=$row['15'].",";
$contents.=$row['16'].",";
$contents.=$row['17'].",";
$contents.=$row['18'].",";
$contents.=$row['19'].",";
$contents.=$row['20'].",";
$contents.=$row['21']."\n";
}
$contents_final = chr(255).chr(254).mb_convert_encoding($contents, "UTF-16LE","UTF-8");
print $contents_final;
}
答案 0 :(得分:1)
使用此:
echo "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
while ($row = mysql_fetch_row($myquery)) {
fputcsv(STDOUT, $row);
}
答案 1 :(得分:1)
我不确定你是否已经开始工作了。但是我对你的代码做了一些改动。
以下是代码:
if (isset($_POST['csvextract'])) {
$name = "sample";
$file = $name . ".csv";
$delimiter = ',';
$con = mysql_connect("localhost", "root");
if (!$con) {
echo "Error connection";
exit;
}
$select_db = mysql_select_db('outbound', $con);
if (!$select_db) {
echo "Error to select database";
exit;
}
mysql_set_charset("utf8", $con);
header("Content-type: text/csv; charset=UTF-8");
header('Content-disposition: attachment; filename=' . basename($file));
$myquery = mysql_query("SELECT * FROM temp");
//While loop to fetch the records
$contents = "Name, Company, Address1, Address2, City, Province, Postal Code, Contact No, Email, Commodity, Type, Weight, Length, Width, Height, Decreased Value, Special Instruction, Shipping Reference, Payment Method, Package No, Tracking No\n";
while ($row = mysql_fetch_array($myquery)) {
for ($i = 0; $i < 22; $i++) {
if (false === strpos($row[$i], $delimiter)) {
$contents .= '"' . $row[$i] . '"';
} else {
$contents.=$row[$i];
}
if ($i === 21) {
$contents .= "\n";
} else {
$contents .= $delimiter;
}
}
}
$contents_final = chr(255) . chr(254) . mb_convert_encoding($contents, "UTF-16LE", "UTF-8");
print $contents_final;
}
我改为跟随。
$i
是否为21,因为我们需要转到新行。如果这不起作用,请告诉我我会修复它。请注意,我没有尝试过这段代码。