插入查询后更新状态

时间:2014-01-09 08:52:58

标签: php mysql

$stmt = "insert into {CI}payment_logs (customer_id, invoice_id, invoice_total_amount, invoice_paid_amount, customer_paid_amount, invoice_payment_on ) "
                . "values( ?, ?, ?, ?, ?, NOW() )";
$this->db->query( $stmt, array( $Customer_Id, $Invoice_Id, $Invoice_Total_Amount, $Deducted_Amount, $Paid_By_Cust ) );        
$Log_Id = $this->db->insert_id(); // Returns Last Insert ID

根据我的需要,这是正常工作,但我必须在特定条件下更新同一个表中每一行的状态。看看图片,

Insert Query

这是上述查询的插入数据。正如您在invoice_total_amount中看到的那样是总金额,但是这个数量在第三行数据中完成。在高亮点数量SUM等于invoice_status之后,我必须将paid字段更新为invoice_total_amount,在其余字段中,我必须将状态更新为partial 。我尝试更新状态以添加触发器但不成功。

然后我尝试使用此命令使用PHP。

update {CI}payment_logs 
    set invoice_status = IF( invoice_total_amount = sum(invoices_paid_amount), 'paid', 'partial' ) 
where log_id = ?

但我没有得到invoices_paid_amount的SUM,其中invoice_id = 5,我尝试在IF条件下使用子查询,但它无效我的查询。

请帮我解决一下查询或触发解决方案..

1 个答案:

答案 0 :(得分:4)

加入计算总和的子查询。

UPDATE {CI}payment_logs l1
JOIN (SELECT invoice_id, SUM(invoices_paid_amount) total
      FROM {CI}payment_logs
      GROUP BY invoice_id) l2
ON l1.invoice_id = l2.invoice_id
SET invoice_status = IF(invoice_total_amount = total, 'paid', 'partial')
WHERE log_id = ?