Question

我有一个表（设施），其中字段名称是swimming_pool，餐厅，WiFi，图书馆等。如果一个特定的房子只有两个可用的设施，我给那些可用的字段名称值1，如果不是0。我想检索值为1的所有字段名称，并使用备用名称回显值为1的每个字段。

这是我想要实现的目标

    $st = $db->prepare(select * from facility where house_id = ?);
    $st->execute(array($_GET['house_id']));
    $row = $st->fetch();

从上面我必须选择值为1的所有字段。对于所有那些值为1的字段，我必须回显名称（例如：如果swimming_pool值为1，我必须回显游泳池，如果它是0则检查下一栏）

我希望你明白我的目标。

Answer 1

我希望我解决了你的问题？我还没有测试它，所以如果可能有问题，请做一个评论。

<?php
/*
* Sample Link: web.com/index.php?house_id=1&search=1,0,0,1
*/

/*
* Sample Fields:
* swimming_pool, restaurant, wifi, library
*/

//Explode the $_GET['search'] to create an array
$fields_to_search = explode(",",$_GET['search']);

//Manually set the fields
$db_fields = [
        'swimming_pool',
        'restaurant',
        'wifi',
        'library'
];

$fields_to_be_selected = "";

//Create a counter as basis to store if the Link is 1 or 0, then pass it to $db_fields[]
$counter = 0;
foreach($fields_to_search as $field) {
    //Check if $field is 1
    if($field == 1) {
        //Then pass it to $table_to_be_selected and add a COMMA
        $fields_to_be_selected .= $db_fields[$counter].",";
    }
    $counter++;
}
//Remove the last COMMA
$fields_to_be_selected = substr($fields_to_be_selected,0,-1);

/*
* LASTLY DO THE prepare()
*/
$query = sprintf("SELECT %s FROM `facility` WHERE `house_id` = ?",$fields_to_be_selected);
$stmt = $db->prepare($query);
$stmt->execute(array($_GET['house_id']));
$rows = $stmt->fetchAll();


//It will only print the selected fields
print_r($rows);

?>

PDO检索值为1的所有字段，并使用备用名称回显

1 个答案: