如何拉出行仅包含特定字符串

Question

我想要一个命令，只输出以“COLOR =”开头的行，然后只有RED，GREEN，YELLOW，BLUE，MAGENTA，CYAN，WHITE或BLACK。每个颜色用“|”分隔，顺序可以改组，指定的颜色可以重复，并且大小写被忽略）。非常感谢任何帮助！

例如，我有一个包含以下行的文件......

COLOUR=ACK|RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|  
COLOUR=ACK|RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN     |WHITE|    TOMORROW  
COLOUR=RED|GREEN|yellow|BLUE|MAGENTA|CYAN|white      
COLOUR=*BL*ACK|RE D|GREEN|YELLOWabc|  
COLOUR=BLACK|green|YELLOW|RED|WHiTE|BLUE|MAGENTA|CYAN  
COLOUR=BLACK|GR  
COLOUR=BLACK  
COLOUR=BLACK|
COLOUR=BLACK|BLACK|BLACK  
COLOUR=RED|RED|RED|BluE|YELLOW|yellow|CYAN|black  
COLOUR=COLOUR = COLOUR  
COLOUR=RED|HELLO|THANKS

这是我需要的输出：

COLOUR=RED|GREEN|yellow|BLUE|MAGENTA|white  
COLOUR=BLACK|green|YELLOW|RED|WHiTE|BLUE|MAGENTA|CYAN  
COLOUR=BLACK  
COLOUR=BLACK|BLACK|BLACK  
COLOUR=RED|RED|RED|BluE|YELLOW|yellow|CYAN|black  

Answer 1

我想你是在COLOUR=之后跟着一个零或多个(RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|BLACK)的序列，接着是一个管道，接着是最后一个颜色，后面跟着一个管道，所有情况 - 不敏感的：

grep -Ei '^COLOUR=((RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|BLACK)\|)*(RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|BLACK)\|?$'

根据您的输入文件，它会生成所需的输出：

COLOUR=RED|GREEN|yellow|BLUE|MAGENTA|CYAN|white
COLOUR=BLACK|green|YELLOW|RED|WHiTE|BLUE|MAGENTA|CYAN
COLOUR=BLACK
COLOUR=BLACK|BLACK|BLACK
COLOUR=RED|RED|RED|BluE|YELLOW|yellow|CYAN|black

Answer 2

尝试使用以下perl 单行

perl -F'=|\|' -lane 'shift @F eq "COLOUR" and grep {!/RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|BLACK/i} @F or print' file

输出

COLOUR=RED|GREEN|yellow|BLUE|MAGENTA|CYAN|white
COLOUR=BLACK|green|YELLOW|RED|WHiTE|BLUE|MAGENTA|CYAN
COLOUR=BLACK
COLOUR=BLACK|BLACK|BLACK
COLOUR=RED|RED|RED|BluE|YELLOW|yellow|CYAN|black

Answer 3

$ awk '
    BEGIN{ c="RED|GREEN|YELLOW|BLUE|MAGENTA|CYAN|WHITE|BLACK" }
    toupper($0) ~ "^COLOUR=(" c ")([|](" c "))*$"
' file
COLOUR=RED|GREEN|yellow|BLUE|MAGENTA|CYAN|white
COLOUR=BLACK|green|YELLOW|RED|WHiTE|BLUE|MAGENTA|CYAN
COLOUR=BLACK
COLOUR=BLACK|BLACK|BLACK
COLOUR=RED|RED|RED|BluE|YELLOW|yellow|CYAN|black