基于索引将数组拆分为Ruby中的多个数组

Question

我有以下数组：

array = [["Group EX (Instructor)", 0.018867924528301886], ["Personal Reasons", 0.018867924528301886]]

我需要动态地将这个数组分成两个数组：

text_array = ["Group EX (Instructor)", "Personal Reasons"]

number_array = [0.018867924528301886,0.018867924528301886]

我目前正在这样做，这不是正确的方法：

array.each do |array|
  text_array << array[0]
  number_array << array[1]
end

Answer 1

只需使用#transpose。

array = [["Group EX (Instructor)", 0.018867924528301886], ["Personal Reasons", 0.018867924528301886]]
a1, a2 = array.transpose
#=> [["Group EX (Instructor)", "Personal Reasons"],
 [0.018867924528301886, 0.018867924528301886]]

修复现有代码，

text_array = array.map { |x| x[0] } #give back first element of each subarray
number_array = array.map { |x| x[1] } #give back second element of each subarray

Answer 2

我会这样做：

array = [["Group EX (Instructor)", 0.018867924528301886], ["Personal Reasons", 0.018867924528301886]]
text_array,number_array = array.flatten.partition{|e| e.is_a? String }
text_array # => ["Group EX (Instructor)", "Personal Reasons"]
number_array # => [0.018867924528301886, 0.018867924528301886]

Answer 3

这也有效：

text_array, number_array = array.first.zip(array.last)

但transpose显然是你想要的。