Question

我们都知道要转换字符串中的值，我们可以按照

进行操作

char* buffer = ... allocate a buffer ...
int value = 4564;
sprintf(buffer, "%d", value);

但是如果我想将数据转换为整数缓冲区而不是字符缓冲区，我们该怎么办呢，基本上我想做以下

int* buffer = ... allocate a buffer ...
int value = 4564;
sprintf(buffer, "%d", value);

提前致谢

Answer 1

确保将缓冲区定义为“value”的值，而不是指向“value”地址的指针。见下文：

#include <stdlib.h>
#include <stdio.h>
#include <memory.h>

int main(int argc, char** argv)
{
    /* Allocate memory. */
    int* buffer = malloc(sizeof(int));

    int value = 1000;

    /* Sets the number stored in buffer equal to value. */
    *buffer = value;

    /* prints 1000 */
    printf("%d\n", *buffer);

    /* Change value to show buffer is not pointing to the address of 'value'. */
    value = 500;

    /* Still prints 1000. If we had used 
    int* buffer = &value, it would print 500. */
    printf("%d\n", *buffer);

    return 0;
}

如何将值转换为整数类型字符串？

1 个答案: