Question

所以问题是：设计一个接受整数参数的函数，并返回从1到作为参数传递的数字的所有整数之和。例如，如果将50作为参数传递，则该函数将返回1,2,3,4 ...... .50的总和。使用递归计算总和。我可以通过我的代码告诉我很多麻烦

def main():
    numbers= int(input('Enter a number to add the sums: ')
    mysum = sum_num(numbers,1)


def sum_num(numbers,mysum):
    start=1
    end=numbers
    if start>end:
        return 0
    else:
        return my_sum
main()

Answer 1

def sumup(n):
    # this one is your emergency break. you return 1 if n gets below
    # a certain threshold, otherwise you'll end up with an infinite
    # loop
    if n <= 1:
        return n
    # here is the recursion step, we return (n + "the sum to n+1")
    else:
        return n + sumup(n-1)

print(sumup(50))

Answer 2

打高尔夫球：

def sumup(n):
    return (n + sumup(n - 1) if n > 1 else n) if isinstance(n, int) else None

python中的递归函数添加？

2 个答案: