Question

我试图找出如何在php和C＃中获得相同的结果。我在c＃中有这段代码：

string date_server = "201311060930|aabbcc@test.com|test";
SHA1 sha_1 = new SHA1CryptoServiceProvider();
byte[] array = Encoding.ASCII.GetBytes(date_server);
array = sha_1.ComputeHash(array);

结果是：2201676219018622422190124192121212501517223823286232147

所以我想在PHP中获得相同的结果：

代码：

$finalString = "201311060930|aabbcc@test.com|test";
$a = utf8_encode($finalString);
$b = unpack('C*', $a); 
$string = implode($b);
$sHash = sha1($string);

但我无法获得相同的结果：3f24039aeb68e306f93161a9e9df2c44e7e1ce15

由于

Answer 1

只需运行你的c＃代码，结果应为

array = {68,176,83,152,44,38,107,201,112,139,17,80,242,94,158,181,136,198,98,193}

我不知道2201676219018622422190124192121212501517223823286232147来自哪里

如果第二个参数为真，

sha1将返回原始结果，您可以通过array

将其转换为byte[]（C＃中的unpack}

$finalString = "201311060930|aabbcc@test.com|test";
$sHash = sha1($finalString, true);
echo join(',',unpack('C*', $sHash));

，输出与C＃

相同

68,176,83,152,44,38,107,201,112,139,17,80,242,94,158,181,136,198,98,193

C＃中的等效PHP sha1

1 个答案: