使用Count（*）As时如何从mysql获得结果

Question

如果我的查询如下，我怎样才能得到结果：

$query = "SELECT COUNT(*) AS call_count FROM `callsepaug` ";
        $query .= "WHERE start_time BETWEEN '" . $start_date . "' AND ";
        $query .= "'" . $end_date . "'";

Answer 1

与简单查询相同，您get count(*)可以call_count

$queryBuild = "SELECT COUNT(*) AS call_count FROM `callsepaug` ";
        $queryBuild .= "WHERE start_time BETWEEN '" . $start_date . "' AND ";
        $queryBuild .= "'" . $end_date . "'");

$query = mysqli_query($queryBuild);

$result =  mysqli_fetch_array($query);

echo $result['call_count'];

或使用对象

$query = "SELECT COUNT(*) AS call_count FROM `callsepaug` ";
        $query .= "WHERE start_time BETWEEN '" . $start_date . "' AND ";
        $query .= "'" . $end_date . "'";

$result = mysqli_query($link, $query);

$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
echo $row["call_count"];

Answer 2

试试这样：

<?php
$query = "SELECT COUNT(*) AS call_count FROM `callsepaug` ";
        $query .= "WHERE start_time BETWEEN '" . $start_date . "' AND ";
        $query .= "'" . $end_date . "'";
$result = $mysqli->query($query);
$row_array=$result->fetch_array(MYSQLI_ASSOC);
print($row_array['TOTALFOUND']); 

注意：不推荐使用Mysql_ *函数。避免使用这些功能。

Answer 3

顺便说一下，你可以用这种方式编写代码......

$query = "
SELECT COUNT(*) call_count 
  FROM callsepaug
 WHERE start_time BETWEEN '$start_date' AND '$end_date';
 ";

Answer 4

试试这个：

$query = mysql_query("SELECT COUNT(*) AS call_count FROM `callsepaug` ";
        $query .= "WHERE start_time BETWEEN '" . $start_date . "' AND ";
        $query .= "'" . $end_date . "'");

$result =  mysql_fetch_array($query);

echo $result[0];