Create an application containing an array that stores 20 double values,
such as 2.34, 7.89, 1.34, and so on. The application should:
* Display the sum of all the array elements
* Display the average of all the array elements
* Display the largest value of all the array elements
这是一个java类赋值。我的成绩不好,因为我的教授说我使用的是数字文字。我在40分中输掉了28分。我设计的解决方案是如此糟糕吗?他的确切评论:
"The program you submitted uses numeric literals in place of the array’s length.
This cause several runtime errors when I change the size of your array and tested the code."
和我的解决方案:
import java.util.Random;
import java.util.Arrays;
public class MyArray{
public static double[] doubles;
public static void main(String args[]) {
MyArray.createDoublesArray();
MyArray.displayDoublesArray();
MyArray.displaySum();
MyArray.displayAverage();
MyArray.displayTheLargestValue();
}
/*Fill up the double Array class member*/
public static void createDoublesArray(){
doubles = new double[20];
//Create Random object
Random r=new Random();
double rangeMin = 1, rangeMax = 9;
//Generate random double number - 20 times within the range of 2 to 9
for(int i=0;i<20;i++) {
//Generate random double numbers and round them to the two decimal places
double randomdouble = Math.round((rangeMin + (rangeMax - rangeMin) * r.nextDouble())*100.0)/100.0;
doubles[i] = randomdouble;
}
}
/*Display the double Array*/
public static void displayDoublesArray(){
String delimiter;
Arrays.sort(doubles);
System.out.println("The double array: ");
// iterate through all the array elements
System.out.print("{");
for(int i=0;i<20;i++) {
if(i < 19){
delimiter = ", ";
}
else{
delimiter = "}";
}
System.out.print(doubles[i]+ delimiter);
}
System.out.println("\n");
}
/*Displays the sum of the double array.*/
public static void displaySum() {
//initialize the sum with 0
double sum = 0.0;
// iterate through all the array elements
for (int i = 0; i < doubles.length; i++) {
// add up each element to the sum variable
sum += doubles[i];
}
// display the sum
System.out.println("The sum is: " + Math.round(sum*100.0)/100.0 + "\n");
}
/*Displays the average of the double array.*/
public static void displayAverage() {
// initialize the sum with 0
double sum = 0.0;
// iterate through all the array elements
for (int i = 0; i < doubles.length; i++) {
sum += doubles[i];
}
// display the average by dividing the sum to the length of the array
System.out.println("The average is: " + Math.round((sum / doubles.length)*100.0)/100.0 + "\n");
}
/*Displays the largest value from the double array */
public static void displayTheLargestValue() {
//initialize the largest value with the first element
double largestValue = doubles[0];
//iterate through the remaining elements (ignore the first)
for (int i = 1; i < doubles.length; i++) {
// check if "i" element is greater then the current largest value
if (doubles[i] > largestValue) {
largestValue = doubles[i];
}
}
// display the largest value
System.out.println("The largest value is: " + largestValue);
}
}
答案 0 :(得分:3)
我猜这不是以下的事情
for(int i=0;i<20;i++)
他希望您使用length
属性
for(int i=0;i<doubles.length;i++)
另外,这里
//initialize the largest value with the first element
double largestValue = doubles[0];
你假设doubles
不为空,当它为空时,会抛出异常
答案 1 :(得分:2)
为了让我们能够轻松维护这段代码,我首先要创建:
private final static int SIZE = 20;
createDoublesArray :
public static void createDoublesArray(){
doubles = new double[SIZE];
//Create Random object
Random r=new Random();
double rangeMin = 1, rangeMax = 9;
//Generate random double number - 20 times within the range of 2 to 9
double randomdouble = 0.0; // <- we don't want to initiate double in 'for' loop
for(int i=0;i<SIZE;i++) {
//Generate random double numbers and round them to the two decimal places
randomdouble = Math.round((rangeMin + (rangeMax - rangeMin) * r.nextDouble())*100.0)/100.0;
doubles[i] = randomdouble;
}
}
displayDoublesArray:
/*Display the double Array*/
public static void displayDoublesArray(){
String delimiter;
Arrays.sort(doubles);
System.out.println("The double array: ");
// iterate through all the array elements
StringBuilder buff = new StringBuilder(); // use buffer
buff.append("{");
for(int i=0;i<SIZE;i++) {
if(i < SIZE-1){
delimiter = ", ";
}
else{
delimiter = "}";
}
buff.append(doubles[i]+ delimiter);
}
buff.append("\n");
System.out.println(buff.toString());
}
我们的代码似乎更通用,我可以更改SIZE
(如果需要),而无需实际更改我的代码。
答案 2 :(得分:1)
我同意Maxim Shoustin ......
只需添加一条评论
1)不要总是使用double。例如。
double rangeMin = 1, rangeMax = 9; //can be replaced by int.