Question

让我们考虑一下这个问题

select class_id,case when event_id=2 then sum(time_spent) end as timespent ,case when event_id=3 then sum(timespent) end as visitedtimespent from class group by class_id,event_id;

输出看起来像

class_id     timespent visitedtimespent

1             2000       NULL
1             NULL        10
2             4000       NULL
2             NULL        5

当我使用此查询时

select class_id,case when event_id=2 then sum(time_spent) end as timespent ,case when event_id=3 then sum(time_spent) end as timespent from class group by class_id;

输出看起来像

class_id     timespent visitedtimespent

1             2000       NULL
2             4000       NULL

但我期待这个输出

class_id     timespent visitedtimespent

1             2000        10
2             4000         5

我怎样才能做到这一点？

Answer 1

select class_id,
       sum(case when event_id=2 then time_spent else 0 end) as timespent, 
       sum(case when event_id=3 then time_spent else 0 end) as visitedtimespent
from class 
group by class_id

Answer 2

总结一下。

    select class_id,
sum(case when event_id=2 then time_spent end) as timespent ,
sum(case when event_id=3 then time_spent end) as visitedtimespent
from class group by class_id;

解释差异： case when id... then sum(value)相当于

select case when id then value from
(
    select id, sum(value) as value from table
)subquery

这是非法分组（ID未汇总或包含在分组中，因此ID值将在所有现有条目之间随机选择），并且您的ID信息将丢失。如果您然后将案例应用于ID信息，则不会得到相关结果。

如何在mysql中合并列的值

2 个答案: