我正在尝试使用JWPlayer在我的网站上播放视频。但我无法动态地从php提供视频,因为我收到以下错误:
Error loading media: File could not be played
我目前的代码是:
<?php
include('connection.php');//connect to db
$id = $_GET['id'];//get video id from param
$video = mysql_query("SELECT * FROM video_table WHERE id = '$id'");//video row from db
$data = mysql_fetch_assoc($video);
$ext = pathinfo($data['video_name'], PATHINFO_EXTENSION);
$file_name = $id . "." . $ext;
echo $file_name;
?>
<div id="container1"></div>
<script type="text/javascript">
jwplayer('container1').setup({
'id': 'container1',
'type': '<?php echo $ext ?>',
'wmode': 'transparent',
'flashplayer': 'jwplayer/jwplayer.flash.swf',
'file': 'video.php',
'provider': 'video',
'width': '480',
'height': '320',
});
</script>
</div>
video.php
<?php
include('connection.php');
$id = $_GET['id'];
$video = mysql_query("SELECT * FROM video_table WHERE id = '$id'");
$data = mysql_fetch_assoc($video);
$ext = pathinfo($data['video_name'], PATHINFO_EXTENSION);
$type = pathinfo($data['type'], PATHINFO_EXTENSION);
$file_name = $id . "." . $ext;//set the file name as saved in upload directory e.g: 1.mp4
header("pragma : no-cache");
header("Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0");
header("Content-Description: File Transfer");
header("Content-Type: $type");
header("Content-Location: upload/$file_name");
header("Content-Transfer-Encoding: binary");
header("Content-Length: ".filesize("upload/$file_name"));
readfile("upload/$file_name");
?>
但是,如果我在此更改了绝对名称(upload/1.mp4) instead of (upload/$file_name)
,则可以使用并提供视频。如何从参数中动态获取视频?
答案 0 :(得分:1)
变化:
'provider': 'video',
要:
'type': 'mp4',
如果您使用FLV而不是MP4,请将其设为:
'type': 'flv',
此外:
这里有一些事情。您仍然将提供商设置为视频,我会删除它。您也将文件作为video.php拉入,但没有设置ID。现在你正在使用 - 'file':'video.php',我会把它改成video.php?id = 1,我也会从6.4更新到6.6。