Question

编写与某个帖子相关的所有“喜欢”的php / mysql代码的最短路径是什么，甚至可以显示点击了like按钮的人，如下例所示：

John，Mary，Brian和其他人喜欢这条评论

Answer 1

由于您没有提供除您想要的任何其他详细信息，因此这完全基于您可以如何设置数据库的假设。

SQL查询：

 SELECT * FROM likes WHERE (comment or post id) = 'ID'

post_id是你想要分组的东西，所以例如，如果每个评论都有自己的ID，那么你想用它来分组你的喜欢。

我的数据库我确实喜欢这样设置：

字段：id，comment_id，post_id，name

所以你会喜欢它：

+--------------+---------------+--------------+--------------+
|    ID        |   comment_id  |    post_id   |   name       |
+--------------+---------------+--------------+--------------+
|     1        |     382       |     null     |   John       |
|     2        |     382       |     null     |   Mary       |
|     3        |     null      |     189      |   Brian      |
|     4        |     null      |     189      |   Joe        |
|     5        |     382       |     null     |   Ryan       |
|     6        |     382       |     null     |   Bell       |
+--------------+---------------+--------------+--------------+

因此，如果您使用SQL脚本：

SElECT * FROM likes WHERE comment_id = '382'

您将获得以下内容：

+--------------+---------------+--------------+--------------+
|    ID        |   comment_id  |    post_id   |   name       |
+--------------+---------------+--------------+--------------+
|     1        |     382       |     null     |   John       |
|     2        |     382       |     null     |   Mary       |
|     5        |     382       |     null     |   Ryan       |
|     6        |     382       |     null     |   Bell       |
+--------------+---------------+--------------+--------------+

然后你会运行一个脚本（假设它是PHP）：

$num = 0; // This is used as an identifier
$numrows = mysqli_num_rows($getdata); // Count the number of likes on your comment or post

if($numrows > 3) { 
    $ending = 'and others like this comment.'; // If there are more than 3 likes, it ends this way
} else { 
    $ending = 'like this comment.'; // If there are less than or equal to 3 likes, it will end this way
}

while($data = mysqli_fetch_array($getdata)) {
    if($num => 3) { // This says that if the $num is less than or equal to 3, do the following
        // This will be used to list the first 3 names from your database and put them in a string like: name1, name2, name3, 
        $names = $data['name'].', ';
        // This adds a number to the $num variable.
        $num++;
    }
}

echo $names.' '.$ending; //Finally, echo the result, in this case, it will be: John, Mary, Ryan, and other like this comment.

php mysql＆＃34; like button＆＃34;通知

1 个答案: