Question

我正在java中开发一个小的Spring和hibernate基础应用程序，我的应用程序与Employee和Unit 有一个很强的关系，Employee有一个单元，Unit有很多Employee。在这个小应用程序genarate错误像这样`

我是硬代码数据到单元模式表，我填充单元组合框填充jsp它的工作原理，但@controller单元里面有一个空数据。

com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException：列'unit_id'不能为空

如果允许null为unit_id的其他数据插入插入unit_id

这是我的实体类

@Entity
@Table(name = "employee")
public class Employee implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)

    @Column(name = "id")
    private Integer id;

    @Column(name = "epf")
    private int epf;

    @Column(name = "fname")
    private String fname;

    @Column(name = "lname")
    private String lname;

    @Column(name = "email")
    private String email;

    @JoinColumn(name = "unit_id", referencedColumnName = "id")
    @ManyToOne//(optional = false)
    private Unit unit;


@Entity
@Table(name = "unit")
public class Unit implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    private Integer id;

    @Column(name = "name")

我的控制器类

 @Autowired
        private EmployeeService employeeService;
        private DesignationService designationService;

        @RequestMapping({"/index", "/"})
        public String setupForm(Map<String, Object> map){
            Employee student = new Employee();
            map.put("employee", student);
            map.put("employeeList", employeeService.getAllEmployee());
map.put("unitList", employeeService.getAllUnitList());

            return "employee";
        }

@RequestMapping(value="/employee.do", method=RequestMethod.POST)
    public ModelAndView doActions(@ModelAttribute Employee emp, BindingResult result, @RequestParam String action, Map<String, Object> map){
        ModelAndView modelAndView = new ModelAndView("employee");

        Employee employeetResult = new Employee();
        switch(action.toLowerCase()){   //only in Java7 can put String in switch
        case "add":
            employeeService.addEmployee(emp);
            employeetResult = emp;
            break;
        case "edit":
            employeeService.updateEmployee(emp);
            employeetResult = emp;
            break;
        case "delete":
            employeeService.deleteEmployee(emp.getId());
            employeetResult = new Employee();
            break;
        case "search":
            Employee searchedStudent = employeeService.getEmployee(emp.getId());
            employeetResult = searchedStudent!=null ? searchedStudent : new Employee();
            break;
        }
        map.put("employee", employeetResult);
        map.put("employeeList", employeeService.getAllEmployee());
        return modelAndView;
    }

我的JSP

<form:form action="employee.do" method="POST" commandName="employee">
  <table width="341" border="0">
    <tr>
      <td width="154">&nbsp;</td>
      <td width="21">&nbsp;</td>
      <td width="152">&nbsp;</td>
    </tr>
    <tr>
      <td><spring:message code="employee.id"/></td>
      <td>&nbsp;</td>
      <td><form:input path="epf" /></td>
    </tr>
    <tr>
      <td><spring:message code="employee.epf"/></td>
      <td>&nbsp;</td>
      <td><form:input path="epf" /></td>
    </tr>
    <tr>
      <td><spring:message code="employee.fname"/></td>
      <td>&nbsp;</td>
      <td><form:input path="fname"/></td>
    </tr>
    <tr>
      <td><spring:message code="employee.lname"/></td>
      <td>&nbsp;</td>
      <td><form:input path="lname" /></td>
    </tr>

    <tr>
      <td><spring:message code="employee.email"/></td>
      <td>&nbsp;</td>
      <td><form:input path="email" /></td>
    </tr>

    <tr>
      <td><spring:message code="employee.unit"/></td>
      <td>&nbsp;</td>

<!-- Unit Combo filling --><td>
     <form:select path="unit" multiple="false" size="1">
        <form:options items="${unitList}" itemValue="id" itemLabel="name"/>
     </form:select>
<!-- Unit Combo filling end --></td>
    </tr>
    <tr>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
      <td>&nbsp;</td>
    </tr>
    <tr>
    <td colspan="2">
      <input type="submit" name="action" value="Add" />
      <input type="submit" name="action" value="Edit" />
      <input type="submit" name="action" value="Delete" />
      <input type="submit" name="action" value="Search" />
    </td>
    </tr>
  </table>
</form:form>

我的DAO课程

> @Repository public class EmployeeDaoImp implements EmployeeDao {
> 
>   @Autowired  private SessionFactory sessionfactory;
>           public void addEmployee(Employee emp) {         sessionfactory.getCurrentSession().save(emp);
> 
>   }
> 
>       public void updateEmployee(Employee emp) {
>       sessionfactory.getCurrentSession().update(emp);
> 
>   }
> 
>       public void deleteEmployee(int id) {
>               sessionfactory.getCurrentSession().delete(getEmployee(id));     }
> 
>    Employee   public Employee getEmployee(int empId) {
>               return (Employee) sessionfactory.getCurrentSession().get(Employee.class,empId);     }
> 
>       public List getAllEmployee() {
>               return sessionfactory.getCurrentSession().createQuery("from Employee").list();  }

Answer 1

id是DB中的主键。您保存对象而不提供其值。所以要么在表中自动增加，要么使用hibernate生成它的值。

Spring-Hibernate插入错误与列＆＃39; unit_id＆＃39;不能为null异常

1 个答案: