有没有比以这种方式编写System.out.println
更好的解决方案?
String nl = System.getProperty("line.separator");
for (k=0; k<=ds.size()-counter-1; k=k+counter){
System.out.println (metric+" "+ds.get(k)+" "+ds.get(k+2)+" sensor=A cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+3)+" sensor=B cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+4)+" sensor=C cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+5)+" sensor=D cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+6)+" sensor=E cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+7)+" sensor=F cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+8)+" sensor=G cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+9)+" sensor=H cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+10)+" sensor=I cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+11)+" sensor=L cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+12)+" sensor=M cell="+ cellName + nl +
metric+" "+ds.get(k)+" "+ds.get(k+13)+" sensor=N cell="+ cellName);
}
答案 0 :(得分:5)
创建一个StringBuilder,将你的字符串附加到StringBuilder,然后在一个System.out.println调用中打印它。
哦,你可以轻松地嵌套两个for循环,让你的代码更具可读性。
如,
StringBuilder stringBuilder = new StringBuilder();
Formatter formatter = new Formatter(stringBuilder);
int maxSomething = 12;
String template = metric + " %s %s sensor=%c cell=" + cellName + nl;
for (int i = 0; i < ds.size()-counter-1; i = i + counter) {
for (int j = 0; j < maxSomething; j++) {
formatter.format(template, ds.get(i), ds.get(i + j + 2), (char)('A' + j));
}
}
// the toString() below isn't necessary but is present for clarity
System.out.println(stringBuilder.toString());
formatter.close();