Question

我正在尝试使用java +打开CMD将代码应用于它以打开.jar，以便应用程序输出显示在.bat文件中。谁能告诉我怎么做？

这是它得到的代码，它确实运行超出文件，但CMD没有显示。

btnTest.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent arg0) {
            String Bat = "C:"+File.separatorChar+"Users"+File.separatorChar+"Gebruiker"+File.separatorChar+"AppData"+File.separatorChar+"Local"+File.separatorChar+"Temp"+File.separatorChar+"hexT"+File.separatorChar+"run.bat";
            Runtime rt = Runtime.getRuntime();
            try {
                rt.exec(Bat);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    });

Answer 1

编辑：这对我有用：

String Bat = "C:\\app.bat";  //Try to use \\ as path seperator

try {
    Runtime.getRuntime().exec("cmd /c start " + Bat);
} catch (IOException e) {
    e.printStackTrace();
}

Answer 2

定义：

FileWriter writer;

然后在你的try / catch中执行以下操作：

    try {
        writer = new FileWriter("test.txt");
        Process child = rt.exec(Bat);
        InputStream input = child.getInputStream();
        BufferedInputStream buffer = new BufferedInputStream(input);
        BufferedReader commandResult = new BufferedReader(new InputStreamReader(buffer));
        String line = "";
        try {
            while ((line = commandResult.readLine()) != null) {
         writer.write(line + "\n");              
            }
        writer.close();

        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

这将逐行读取输出作为缓冲区并将其写入文本文件

使用Java应用程序打开.Bat

2 个答案: