Question

我正在尽力解决以下问题：

我想将2个文件（file1.txt和file2.txt）相互比较。第一个文件（file1.txt）包含字典（字符串）。它们用于搜索第二个文件（file2.txt）。如果在file2.txt中找到相同的字符串，则应将其删除。这应该遍历file1中的所有字符串。

我正在使用以下代码：

import csv
import os

    enter code here

crimefile = open('file1.txt', 'r')
reader = csv.reader(crimefile)
allRows = [row for row in reader]

crimefileB = open('file2.txt', 'r')
reader = csv.reader(crimefileB)
allRowsB = [row for row in reader]

for counter in xrange(0,allRowsB.count()):
    print count
    if allRows[count] == allRowsB[count]: allRowsB[count-2].remove
    enter code here

在附加的代码中，我将它们导出到列表中，但我不想在此方法中执行任务。

非常感谢任何帮助。

Answer 1

您可以执行以下操作：

import csv
import os

crimefile = open('file1.txt', 'r')
reader = csv.reader(crimefile)

# Sets are much faster for membership checks.  Also, using a generator 
# (the ()'s) instead of a list will save memory, as the entire file will
# not need to loaded in all at once.
filtervals = set((row for row in reader))

out = []
crimefileB = open('file2.txt', 'r')
reader = csv.reader(crimefileB)
for line in reader:
    if line not in filtervals:
        out.append(line)
# Don't forget to close the files you open!

out将包含由file1.txt过滤的file2.txt。

你也可以做最后一点作为列表理解。

out = [ line for line in reader if line not in filtervals ]

检查我重复的警报并删除，Python

1 个答案: