Question

这个问题仍困扰着我。看起来很简单。我在lib和舞台上有动画片段，它有一个链接类“Box.as”，另一个链接到“Circle.as”。我想从Circle.as访问Box.as的动画片段，反之亦然。

public class Circle extends MovieClip
{
    private var _circle:MovieClip;
    private var _box:Box;


    public function Circle()
    {
        _circle = new MovieClip();

        if (stage) onStage();
        else this.addEventListener(Event.ADDED_TO_STAGE,onStage);


    }
    private function onStage(e:Event = null)
    {
        _circle = stage.getChildByName("blue_circle") as MovieClip;
        this.addEventListener(Event.ENTER_FRAME,hitTarget);

    }

    private function hitTarget(e:Event):void
    {

        if (_circle.hitTestObject(_box.mc)) //test if 2 movieclips are colliding
        { // _box.mc is just created the same as _circle
            trace("hi");
        }

    }

这段代码不起作用。而且我想使用一个即使动画片段不在舞台上也可以访问的（没有实例名称）希望您能够帮助我。感谢。

Answer 1

看起来你真的很亲密！您只是忘了创建班级Box的新实例。因此，在public function Circle()内添加

_box = new Box();

如果有效，请告诉我。如果没有，您的链接可能有问题...

您的整个代码将如下所示

    public class Circle extends MovieClip
{
    private var _circle:MovieClip;
    private var _box:Box;


    public function Circle()
    {
        _box = new Box();
        _circle = new MovieClip();

        if (stage) onStage();
        else this.addEventListener(Event.ADDED_TO_STAGE,onStage);


    }
    private function onStage(e:Event = null)
    {
        _circle = stage.getChildByName("blue_circle") as MovieClip;
        this.addEventListener(Event.ENTER_FRAME,hitTarget);

    }

    private function hitTarget(e:Event):void
    {

        if (_circle.hitTestObject(_box.mc)) //test if 2 movieclips are colliding
        { // _box.mc is just created the same as _circle
            trace("hi");
        }

    }

如何使用链接类访问动态/静态动画片段？

1 个答案: