我有以下两个阵列......
1)我怎么才能得到不同的key->值一? 2)如何向mysql插入第二个数组?
// first array
$aa = Array
(
[t_a] => Array
(
[0] => Array
(
[f_c] => LAL
[p_r] => RN
[id] =>
[gender] => m
)
)
[t_b] => Array
(
)
[t_l] => Array
(
[0] => Array
(
[p_lev] => 2
[p_date] =>
[p_r] =>
)
)
[t_r] => Array
(
[0] => Array
(
[I_r] => 19
)
)
//第二个数组
$bb = Array
(
[t_a] => Array
(
[0] => Array
(
[f_c] => NAN
[p_r] => RN
[id] => 1214125
[gender] => m
)
)
[t_b] => Array
(
)
[t_l] => Array
(
[0] => Array
(
[p_lev] => 2
[p_date] => 21
[p_r] => 25
)
)
[t_r] => Array
(
[0] => Array
(
[I_r] => 19
)
)
我使用了array_diff函数但是我得到了NULL。
请帮助一些人?答案 0 :(得分:1)
$aa=(array)$aa;
$bb=(array)$bb;
$result=array_diff($aa,$bb);
答案 1 :(得分:1)
目前还不清楚你想要什么。请举例或您想要的输出。这是一种可能性:
$ser_aa = array_map(function($e){return serialize($e);}, $aa);
$ser_bb = array_map(function($e){return serialize($e);}, $bb);
$diff = array_diff($ser_aa, $ser_bb);
$out = array_map(function($e){return unserialize($e);}, $diff);
print_r($out);
输出:
Array
(
[t_a] => Array
(
[0] => Array
(
[f_c] => LAL
[p_r] => RN
[id] =>
[gender] => m
)
)
[t_l] => Array
(
[0] => Array
(
[p_lev] => 2
[p_date] =>
[p_r] =>
)
)
)