Question

我有两个对象应用程序和环境列表。我正在添加这些列表，但我将输出作为一个完整的应用程序列表，而不是其他整个环境列表。

我希望它以嵌套的形式存在，例如应用程序和环境的一个条目，而不是应用程序和环境的第二行等等

这是我的代码：

@GET
@Path("/test")
@Produces({MediaType.APPLICATION_JSON, MediaType.APPLICATION_XML})
public ArrayList<MyModel> Test(){

    System.out.println("inside test");

    List<ApplicationDTO> allApplication = applicationService.getAllApplication();

    List<Application> Applist = new ArrayList<Application>();
    List<Environment> Envlist = new ArrayList<Environment>();

    for(ApplicationDTO d: allApplication)
    {
        Application a = new Application();

        a.setApplicationDescription(d.getApplicationDescription());
        a.setApplicationId(d.getApplicationId());
        a.setApplicationName(d.getApplicationName());
        a.setAssignedTo(d.getAssignedTo());
        a.setCreatedBy(d.getCreatedBy());
        a.setCreateTime(d.getCreateTime());
        a.setModifiedTime(d.getModifiedTime());
        a.setOwner(d.getOwner());

        Environment e = new Environment();

        for(EnvironmentDTO en: d.getEnvironment())
        {
            e.setEnvironmentId(en.getEnvironmentId());
            e.setEnvironmentName(en.getEnvironmentName());
            e.setOwner(en.getOwner());
            e.setCreateTime(en.getCreateTime());

            Envlist.add(e);
        }

        Applist.add(a);
    }

    ArrayList<MyModel> obj= new ArrayList<MyModel>();
    MyModel mm = new MyModel();
    mm.setAppDTO(Applist);
    mm.setEnDTO(Envlist);
    obj.add(mm);
    return obj; 
    }

修改

我改变了我的类我在应用程序中添加了环境列表，现在我得到了应用程序内所有环境的列表，但我需要一个应用程序内的一个环境，另一个应用程序内部的其他环境，依此类推。我错过了什么？

    public List<Application> Test(){

    System.out.println("inside test");

    List<ApplicationDTO> allApplication = applicationService.getAllApplication();

    List<Application> Applist = new ArrayList<Application>();
    List<Environment> Envlist = new ArrayList<Environment>();

    for(ApplicationDTO d: allApplication)
    {           
        Application a = new Application();

        a.setApplicationDescription(d.getApplicationDescription());
        a.setApplicationId(d.getApplicationId());
        a.setApplicationName(d.getApplicationName());
        a.setAssignedTo(d.getAssignedTo());
        a.setCreatedBy(d.getCreatedBy());
        a.setCreateTime(d.getCreateTime());
        a.setModifiedTime(d.getModifiedTime());
        a.setOwner(d.getOwner());

        for(EnvironmentDTO en: d.getEnvironment())
        {
            Environment e = new Environment();

            e.setEnvironmentId(en.getEnvironmentId());
            e.setEnvironmentName(en.getEnvironmentName());
            e.setOwner(en.getOwner());
            e.setCreateTime(en.getCreateTime());
            Envlist.add(e);
        }

        a.setEnvlists(Envlist);         
        Applist.add(a);
    }
    return Applist;

Answer 1

您应该创建一个包含应用程序和环境列表的对象，例如ApplicationWithEnvironments。

    List<ApplicationWithEnvironments > AppWithEnvlist = new ArrayList<ApplicationWithEnvironments >();        

    for(ApplicationDTO d: allApplication) {
        ApplicationWithEnvironments appWithEnv = new ApplicationWithEnvironments();

        Application a = new Application();

        a.set...

        appWithEnv.setApplication(a);


        for(EnvironmentDTO en: d.getEnvironment())
        {
            Environment e = new Environment();
            e.set...
            appWithEnv.addEnvironment(e);
        }

        AppWithEnvList.add(appWithEnv);
    }

    ArrayList<MyModel> obj= new ArrayList<MyModel>();
    MyModel mm = new MyModel();
    mm.setAppWithEnvList(AppWithEnvList);
    obj.add(mm);
    return obj;

或者您可以在Application对象中有一个Environments列表，因此您不再需要新的ApplicationWithEnvironments对象。

添加两个列表并以嵌套形式获取XML输出

1 个答案: