使用LINQ的Pivot-table-esque结果

时间:2013-06-28 11:38:31

标签: c# linq

在LINQ中有没有办法做到这一点 - 我现在一直在反对这一点:

来源:

var selectedDate = new DateTime(2013, 1, 1);
var selectedMonth = selectedDate.Month;
var selectedYear = selectedDate.Year;

var data = new List<MyClass>
{
    new MyClass { Date = new DateTime(2013, 1, 1), Val1 = 1, Val2 = 2 },
    new MyClass { Date = new DateTime(2013, 1, 2), Val1 = 1, Val2 = 2 },
    new MyClass { Date = new DateTime(2013, 2, 1), Val1 = 1, Val2 = 2 }
};

Date       | Val1 | Val2
01/01/2013 | 1    | 2
02/01/2013 | 1    | 2
01/02/2013 | 1    | 2

结果(每个Val与日期/月/年的总和):

     | selectedDate | selectedMonth | selectedYear
Val1 | 1            | 2             | 3
Val2 | 2            | 4             | 6

2 个答案:

答案 0 :(得分:1)

我认为LINQ不是解决方案。你可以很容易地获得一个旋转的“行”,但你需要再次枚举序列以获得下一个序列,这不是非常有效(如果源是一个“懒惰”可枚举而且你不会我想把整个序列保存在内存中。)

我认为最简单,最有效的解决方案是标准foreach。如果必须的话,可以使用Aggregate将其转换为LINQ,但它不会那么简单:

        var val1 = new Result();
        var val2 = new Result();
        foreach (var item in data) {
            if (item.Date == selectedDate) {
                val1.Date += item.Val1;
                val2.Date += item.Val2;
            }
            if (item.Date.Month == selectedMonth) {
                val1.Month += item.Val1;
                val2.Month += item.Val2;
            }
            if (item.Date.Year == selectedYear) {
                val1.Year += item.Val1;
                val2.Year += item.Val2;
            }
        }

可能有些方法可以使这更具活力,但这是另一个问题。

答案 1 :(得分:0)

var result = new List<Result>{
    new Result{
      Val = "Val1",
      Date = data.Sum(e => e.Val1 * (e.Date == selectedDate ? 1 : 0)),
      Month = data.Sum(e => e.Val1 * (e.Date.Month == selectedMonth ? 1 : 0)),
      Year = data.Sum(e => e.Val1 * (e.Date.Year == selectedYear ? 1 : 0)),
    },
    new Result{
      Val = "Val2",
      Date = data.Sum(e => e.Val2 * (e.Date == selectedDate ? 1 : 0)),
      Month = data.Sum(e => e.Val2 * (e.Date.Month == selectedMonth ? 1 : 0)),
      Year = data.Sum(e => e.Val2 * (e.Date.Year == selectedYear ? 1 : 0)),
    }
};

使用Result

public class Result {
    public String Val { get; set; }
    public int Date { get; set; }
    public int Month { get; set; }
    public int Year { get; set; }
}