Question

有人请帮忙！这对我来说真的很困惑。我在互联网上找不到能够解释得这么好的人。所以这就是我需要的：我需要有人解释如何在Unity中创建XML文件。人们告诉我要看一个流作家。我已经搜索了这个，但没有人给出如何编写它的教程。我也不知道.NET是什么，所以请不要给我这个答案。我也浏览了微软页面的XML文件，但我找不到正确的答案。这就是我正在寻找的所有内容：

我希望能够写出这样的内容：

<Player>

    <Level>5<\Level>  
    <Health>500<\Health>  

<\Player>

如何创建这样的文件并将其导入Unity？如何让Unity读取此文件并从此类提取信息？对于整个.NET和XML，我总共需要n00b。

Answer 1

假设您有一个 Player 类，如下所示：

[XmlRoot]
public class Player
{
    [XmlElement]
    public int Level { get; set; }

    [XmlElement]
    public int Health { get; set; }
}

这是一个完整的往返途径，可以帮助您入门：

XmlSerializer xmls = new XmlSerializer(typeof(Player));

StringWriter sw = new StringWriter();
xmls.Serialize(sw, new Player { Level = 5, Health = 500 });
string xml = sw.ToString();

Player player = xmls.Deserialize(new StringReader(xml)) as Player;

xml 是：

<?xml version="1.0" encoding="utf-16"?>
<Player xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Level>5</Level>
  <Health>500</Health>
</Player>

你猜播放器与我们序列化的原始对象完全相同。

如果要从文件序列化/反序列化，可以执行以下操作：

using (var stream = File.OpenWrite("my_player.xml"))
{
    xmls.Serialize(stream, new Player { Level = 5, Health = 500 });
}

Player player = null;
using (var stream = File.OpenRead("my_player.xml"))
{
    player = xmls.Deserialize(stream) as Player;
}

修改

如果您想要显示您所显示的XML：

XmlSerializer xmls = new XmlSerializer(typeof(Player)); XmlSerializerNamespaces ns = new XmlSerializerNamespaces(); ns.Add("", ""); XmlWriterSettings settings = new XmlWriterSettings { OmitXmlDeclaration = true, Indent = true }; using (var stream = File.OpenWrite("my_player.xml")) { using (var xmlWriter = XmlWriter.Create(stream, settings)) { xmls.Serialize(xmlWriter, new Player { Level = 5, Health = 500 }, ns); } } Player player = null; using (var stream = File.OpenRead("my_player.xml")) { player = xmls.Deserialize(stream) as Player; }

如何在Unity中用C＃编写XML文件？

1 个答案: