如何在PHP中设置正则表达式

Question

我想知道如何获得以下文本的正则表达式：

XXXXXX[Some Same Text # AAAA-NNNN]XXXXXX

其中：

'X' can vary any text: Alfa, numerical or symbols (The X can have 0 to infinite characters and it is NOT obligatory).
'A' Alfa uppercase text (The Alfa has exactly 4 uppercase letters and it is obligatory).
'N' Numbers (The N have exactly 4 numbers and it is obligatory).
'Some Same text' has exactly the same text always and it is obligatory.
'[,],#,-' will always be there in that same possition and it is obligatory.

我有一个preg_match：

*[Some Same Text([A-Z]{4})-([0-9]{4})]*

它似乎没有起作用。

谢谢和问候！

Answer 1

.匹配任何字符，*表示0..infinity。 使用[和]时，您需要逃避它们。试试这个：

.*\[Some Same Text # ([A-Z]{4})-([0-9]{4})\].*

Answer 2

这应该有效：'/^.*\[Some Same Text\s#\s[A-Z]{4}-\d{4}\].*$/'。经过测试：

if(preg_match('/^.*\[Some Same Text\s#\s[A-Z]{4}-\d{4}\].*$/', 'XXXXXX[Some Same Text # AAAA-4444]XXXXXX'))echo 1;