我修改了计算几何cgal
库(link)给出的示例,该示例演示了在2D平面上的增量搜索(第49.3.2节)。该示例使用仿函数来设置空间边界,以便仅搜索平面上的正点。
我想修改仿函数,以便传递k
,如struct X_not_positive_k
所示。下面的完整示例程序显示了修改后的代码和原始代码。
#include <CGAL/Simple_cartesian.h>
#include <CGAL/Orthogonal_incremental_neighbor_search.h>
#include <CGAL/Search_traits_2.h>
typedef CGAL::Simple_cartesian<double> K;
typedef K::Point_2 Point_d;
typedef CGAL::Search_traits_2<K> TreeTraits;
typedef CGAL::Orthogonal_incremental_neighbor_search<TreeTraits> NN_incremental_search;
typedef NN_incremental_search::iterator NN_iterator;
typedef NN_incremental_search::Tree Tree;
int main() {
Tree tree;
tree.insert(Point_d(0,0));
tree.insert(Point_d(1,1));
tree.insert(Point_d(0,1));
tree.insert(Point_d(10,110));
tree.insert(Point_d(45,0));
tree.insert(Point_d(0,2340));
tree.insert(Point_d(0,30));
Point_d query(0,0);
// A functor that returns true, iff the x-coordinate of a dD point is not positive
// [ORIGINAL CODE]
struct X_not_positive {
bool operator()(const NN_iterator& it) { return ((*it).first)[0]<0; }
};
// [MODIFIED CODE]
// This does not work when used below.
struct X_not_positive_k {
public:
void assign_k(int k) {this->k = k; }
bool operator()(const NN_iterator& it) { return ((*it).first)[0] < k; }
private:
int k;
};
X_not_positive_k Xk;
Xk.assign_k(1);
// An iterator that only enumerates dD points with positive x-coordinate
// [ORIGINAL CODE]
// typedef CGAL::Filter_iterator<NN_iterator, X_not_positive> NN_positive_x_iterator;
// [MODIFIED CODE]
typedef CGAL::Filter_iterator<NN_iterator, X_not_positive_k> NN_positive_x_iterator;
NN_incremental_search NN(tree, query);
// [ORIGINAL CODE]
// NN_positive_x_iterator it(NN.end(), X_not_positive(), NN.begin()), end(NN.end(), X_not_positive());
// [MODIFIED CODE]
NN_positive_x_iterator it(NN.end(), Xk(), NN.begin()), end(NN.end(), Xk());
// error occurs here
std::cout << "The first 5 nearest neighbours with positive x-coord are: " << std::endl;
for (int j=0; (j < 5)&&(it!=end); ++j,++it)
std::cout << (*it).first << " at squared distance = " << (*it).second << std::endl;
return 0;
}
但是,编译此程序(Windows 7与Visual Studio 2010)会导致以下编译器错误。错误的位置标记在上面的代码中。
2>..\main.cpp(56): error C2064: term does not evaluate to a function taking 0 arguments
2> class does not define an 'operator()' or a user defined conversion operator to a pointer-to-function or reference-to-function that takes appropriate number of arguments
2>..\main.cpp(56): error C2064: term does not evaluate to a function taking 0 arguments
2> class does not define an 'operator()' or a user defined conversion operator to a pointer-to-function or reference-to-function that takes appropriate number of arguments
2>
可以做些什么来摆脱错误?还有另一种方法可以设置k
变量吗?
答案 0 :(得分:1)
只需将您的Xk()
替换为第56行中的Xk
或者用构造函数参数替换assign(k)
,然后替换Xk()
与X_not_positive_k(1)
实际上真正的麻烦是算子的名字!将姓名X_not_positive_k
替换为X_less_than
- 因此第56行的X_less_than(1)
调用看起来不错
struct X_less_than {
public:
X_less_than(int i)
: k(i)
{
}
bool operator()(const NN_iterator& it) { return ((*it).first)[0] < k; }
private:
int k;
};
答案 1 :(得分:1)
你的错误在于
NN_positive_x_iterator it(.., X_not_positive(), .. )
X_not_positive
是类型,X_not_positive()
是构造函数的调用,
NN_positive_x_iterator it(.., Xk(),.. )
Xk
不是类型而是对象,Xk()
是对operator()
的调用
这是具有零参数的函数运算符,因此也就是错误消息。
安德烈亚斯