我想用 GD和PHP 模仿Photoshop的修剪行为(裁剪所有方面覆盖相同颜色的区域)但我缺乏关于如何实现这一目标的想法。
如果有人知道如何做到这一点,我非常希望听到它。
提前致谢。
答案 0 :(得分:4)
我能想到的最简单的解决方案是:
未经测试但可能有用。
BTW,ImageMagick可以开箱即用:http://www.imagemagick.org/Usage/crop/#trim
答案 1 :(得分:2)
Here's示例函数(也可以添加填充):
// Trims an image then optionally adds padding around it.
// $im = Image link resource
// $bg = The background color to trim from the image
// $pad = Amount of padding to add to the trimmed image
// (acts simlar to the "padding" CSS property: "top [right [bottom [left]]]")
function imagetrim(&$im, $bg, $pad=null){
// Calculate padding for each side.
if (isset($pad)){
$pp = explode(' ', $pad);
if (isset($pp[3])){
$p = array((int) $pp[0], (int) $pp[1], (int) $pp[2], (int) $pp[3]);
}else if (isset($pp[2])){
$p = array((int) $pp[0], (int) $pp[1], (int) $pp[2], (int) $pp[1]);
}else if (isset($pp[1])){
$p = array((int) $pp[0], (int) $pp[1], (int) $pp[0], (int) $pp[1]);
}else{
$p = array_fill(0, 4, (int) $pp[0]);
}
}else{
$p = array_fill(0, 4, 0);
}
// Get the image width and height.
$imw = imagesx($im);
$imh = imagesy($im);
// Set the X variables.
$xmin = $imw;
$xmax = 0;
// Start scanning for the edges.
for ($iy=0; $iy<$imh; $iy++){
$first = true;
for ($ix=0; $ix<$imw; $ix++){
$ndx = imagecolorat($im, $ix, $iy);
if ($ndx != $bg){
if ($xmin > $ix){ $xmin = $ix; }
if ($xmax < $ix){ $xmax = $ix; }
if (!isset($ymin)){ $ymin = $iy; }
$ymax = $iy;
if ($first){ $ix = $xmax; $first = false; }
}
}
}
// The new width and height of the image. (not including padding)
$imw = 1+$xmax-$xmin; // Image width in pixels
$imh = 1+$ymax-$ymin; // Image height in pixels
// Make another image to place the trimmed version in.
$im2 = imagecreatetruecolor($imw+$p[1]+$p[3], $imh+$p[0]+$p[2]);
// Make the background of the new image the same as the background of the old one.
$bg2 = imagecolorallocate($im2, ($bg >> 16) & 0xFF, ($bg >> 8) & 0xFF, $bg & 0xFF);
imagefill($im2, 0, 0, $bg2);
// Copy it over to the new image.
imagecopy($im2, $im, $p[3], $p[0], $xmin, $ymin, $imw, $imh);
// To finish up, we replace the old image which is referenced.
$im = $im2;
}