Question

下面我列出了我的模型和视图中的一些代码。它告诉我$ date变量不存在。我不明白为什么它不会。我正在改变它作为对象，这就是为什么一些旧代码仍然有$ data-＆gt;以及为什么将其更改为$ data ['']。无论它现在告诉我$ data不存在。

这是我认为的代码。

<?php
$this->widget('bootstrap.widgets.TbGridView', array(
    'type'=>'condensed',
    'dataProvider'=>$gridDataProvider,
    'template'=>"{items}",
    'columns'=>array(
        array('name'=>'id', 'header'=>'Name'),
        array('name'=>'emax', 'header'=>'Employees' 'value'=>$date['id']),
        /*array('name'=>'location', 'value'=>'$data->city . ", " . $data->state->name', 'header'=>'Location'),
        array('name'=>'phone', 'header'=>'Phone'),
        array('name'=>'website', 'header'=>'Website'),
        array(
            'class'=>'bootstrap.widgets.TbButtonColumn',
            'htmlOptions'=>array('style'=>'width: 50px'),
            'template'=>"{view}",
            'buttons'=>array(
                'view'=>array(
                    'url'=>'Yii::app()->createUrl("account/rinkdetail", array("id"=>$data->id))',
                    ),
                ),
        ),*/
    ),
));
?>

这是我的模型中的代码

$sql="SELECT buyer.id, emax.max as emax, emin.min as emin, rmin.min as rmin, rmin.max as rmax, firm.name as firm, region.name as region, project.name as project
FROM buyer
LEFT JOIN buyer_target target on buyer.id=target.buyer_id
LEFT JOIN employee emax on emax.id=target.max_employee_id
LEFT JOIN employee emin on emin.id=target.min_employee_id
LEFT JOIN revenue rmax on rmax.id=target.max_revenue_id
LEFT JOIN revenue rmin on rmin.id=target.min_revenue_id
LEFT JOIN buyer_target_firm tfirm on buyer.id=tfirm.buyer_id
LEFT JOIN firm on firm.id=tfirm.firm_id
LEFT JOIN buyer_target_project tproject on buyer.id=tproject.buyer_id
LEFT JOIN project on project.id=tproject.project_id
LEFT JOIN buyer_target_region tregion on buyer.id=tregion.buyer_Id
LEFT JOIN region on region.id=tregion.region_id";
$gridDataProvider = new CSqlDataProvider($sql);
return $gridDataProvider;

Answer 1

我能够弄清楚。在我上面使用的例子中，它说

'value'=>$date['id']

即使我在我的例子中有DATE，我在实际测试中使用了DATA。它需要的实际问题是什么......

'value'=>'$data["id"]'

Answer 2

替换：

array('name'=>'emax', 'header'=>'Employees' 'value'=>$date['id']),

使用：

array('name'=>'emax', 'header'=>'Employees', 'value'=>$date['id']),

Yii Bootstrap Gridview和CSqlDataProvider没有$ data变量。

2 个答案: