Question

我的联系人模型中有这个：

public static function contacts($perPage = 10)
{
    $order_type = '.desc';
    $order = Session::get('contact.order', 'first_name' . $order_type); // Set the default order to created_at DESC
    $order = explode('.', $order);

    $columns = array(
        'contacts.id as id',
        'contacts.first_name as first_name',
        'contacts.last_name as last_name',
        'contacts.telephone_number as telephone_number',
        'contacts.email as email',
        'accounts.company_name as account',
        'users.first_name as am_first_name',
        'users.last_name as am_last_name'
    );

    $contacts = DB::table('contacts')
        ->leftJoin('accounts', 'account_id', '=', 'accounts.id')
        ->leftJoin('account_managers', 'accounts.account_manager_id', '=', 'account_managers.id')
        ->leftJoin('users', 'user_id', '=', 'users.id')
        ->orderBy($order[0], $order[1])
        ->paginate($perPage, $columns);

    return $contacts;
}

它没有将我的'as'语句分配给我想要的列，这意味着我得到'列first_name是不明确的。

你能否用Paginate方法做到这一点？

干杯

Answer 1

您需要使用select($columns) ...

$contacts = DB::table('contacts')
    ->select($columns)
    // other bits
    ->paginate($perPage);

正如Specifying A Select Clause

所述

如何将列名分配给Laravel paginate（）方法

1 个答案: