我一直试图动态填充我的Google图表,例如: https://developers.google.com/chart/interactive/docs/php_example
我正在为DataTable类和其他人使用此依赖项:
<dependency>
<groupId>com.google.visualization</groupId>
<artifactId>visualization-datasource</artifactId>
<version>1.1.1</version>
</dependency>
这是DataTable类的API: https://developers.google.com/chart/interactive/docs/dev/dsl_javadocs/com/google/visualization/datasource/datatable/DataTable
我正在使用包含此代码(示例)的Java HttpServlet来填充DataTable:
DataTable dataTable = new DataTable();
dataTable.addColumn(new ColumnDescription("uur", ValueType.TEXT, "Uur"));
dataTable.addColumn(new ColumnDescription("aantal", ValueType.NUMBER, "Aantal spellen"));
try {
dataTable.addRowFromValues("1", 5, true);
dataTable.addRowFromValues("2", 9, true);
dataTable.addRowFromValues("3", 17, true);
} catch (TypeMismatchException ex) {
Logger.getLogger(VerkrijgChartDataServlet.class.getName()).log(Level.SEVERE, null, ex);
}
我还包含了这个以使其返回JSON:
response.setContentType("application/json");
然后使用Gson我将其转换为JSON字符串:
new Gson().toJson(dataTable);
返回格式为
的字符串{
"columnIndexById" : {"aantal":1, "uur":0},
"columns" : [
{"id":"uur","label":"Uur","pattern":"","type":"TEXT"},
{"id":"aantal","label":"Aantal spellen","pattern":"","type":"NUMBER"}
],
"rows" : [
{"cells":[{"value":{"value":"1"}},{"value":{"value":5.0}}]},
{"cells":[{"value":{"value":"2"}},{"value":{"value":9.0}}]},
{"cells":[{"value":{"value":"3"}},{"value":{"value":17.0}}]},
],
"warnings" : []
}
但谷歌图表说:'表没有列。' Google的示例JSON如下所示:
{
"cols": [
{"id":"","label":"Topping","pattern":"","type":"string"},
{"id":"","label":"Slices","pattern":"","type":"number"}
],
"rows": [
{"c":[{"v":"Mushrooms","f":null},{"v":3,"f":null}]},
{"c":[{"v":"Onions","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Olives","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Zucchini","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Pepperoni","f":null},{"v":2,"f":null}]}
]
}
有没有人知道我做错了什么?我还需要做点什么吗? 提前完成。
答案 0 :(得分:0)
有点迟,但迟到,从来没有。我想我知道你问题的答案。
你真的知道答案。在您的问题中,您提供了Google Chart JSON示例。 JSON字符串需要以
开头{"cols":...}
,而由gson呈现的JSON字符串以
开头{"ColumnIndexById":{...},
"columns":...
}
如果您将json字符串传递给Google DataTable可视化,那么其结构需要与Google示例完全相同。因此,它不是“列”,而是“cols”。
答案 1 :(得分:0)
您可以使用API的JsonRenderer
JsonRenderer.renderJsonResponse(
DataSourceParameters.getDefaultDataSourceParameters(), null, data
)