我的查询是:
select
C.GradePoint, D.Domain
from
(select
A.course_code, B.course_title, A.GradePoint
from
(select
course_code, GradePoint
from
CoursesResult$
where
roll_number = '42472' and GradePoint != 'I'
and GradePoint != 'F' and GradePoint != 'D-'
and GradePoint != 'D+' and GradePoint != 'D'
and GradePoint != 'C-' and GradePoint != 'C'
and GradePoint != 'C+') A
join Courses$ B on A.course_code=B.course_code) C
join Domains$ D on C.course_title=D.Courses
输出:
GradePoint Domain
1. B+ Software Developer
2. B- Software Developer
3. B- Software Developer
4. B- Project Management
5. B- Business Intelligence and Analytics
6. B+ Business Intelligence and Analytics
7. B+ Business Intelligence and Analytics
8. B- Game Development
9. B Game Development
10. B- Database Administrator
11. B- Database Administrator
12. B Database Administrator
现在每个年级的数字是
我想计算每个域的成绩计数
需要输出:
任何人都可以帮忙吗?
答案 0 :(得分:0)
用这个代替前两行:
select
SUM(CASE C.GradePoint WHEN 'B' THEN 3 WHEN 'B+' THEN 4 WHEN 'B-' THEN 2 ELSE 0 END),
D.Domain
在查询的最后添加GROUP BY D.Domain